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[장희직] - 트리의 지름, 공유기 설치 #249

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43 changes: 43 additions & 0 deletions src/main/kotlin/heejik/60week/공유기 설치.kt
Original file line number Diff line number Diff line change
@@ -0,0 +1,43 @@
package heejik.`60week`

class `공유기 설치` {

fun solve() {
val (n, c) = readln().split(' ').map { it.toInt() }
val homes = MutableList(size = n) { 0L }
repeat(n) {
homes[it] = readln().toLong()
}
homes.sort()

fun canInstall(distance: Long): Boolean {
var now = homes.first()
var installCount = 1
homes.drop(1).forEach { pos ->
if (pos - now >= distance) {
installCount += 1
now = pos
}
}

return installCount >= c
}

var start = 1L
var end: Long = homes.last() - homes.first()

while (start <= end) {
val middle = (start + end) / 2
if (canInstall(middle)) { // 설치가 가능하면 오른쪽을 본다.
start = middle + 1
} else { // 설치가 안되면 왼쪽을 본다.
end = middle - 1
}
}
Comment on lines +29 to +36
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직접 다 계산해서 이렇게 깔끔하게 나오도록 짜시다니 멋지네요

Comment on lines +26 to +36
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이런 방식은 end에 1을 붙이지 않아도 되는군요 ~~

println(end)
}
}

fun main() {
`공유기 설치`().solve()
}
88 changes: 88 additions & 0 deletions src/main/kotlin/heejik/60week/뮤탈리스크.kt
Original file line number Diff line number Diff line change
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package heejik.`60week`

class 뮤탈리스크 {

data class Scves(
val hp1: Int,
var hp2: Int,
var hp3: Int
) {
fun isAllDie() = hp1 <= 0 && hp2 <= 0 && hp3 <= 0
fun countLive(): Int {
var count = if (hp1 > 0) 1 else 0
if (hp2 > 0) count += 1
if (hp3 > 0) count += 1
return count
}

fun getLiveHP(): List<Int> {
val tmp = mutableListOf<Int>()
if (hp1 > 0) tmp.add(hp1)
if (hp2 > 0) tmp.add(hp2)
if (hp3 > 0) tmp.add(hp3)
return tmp
}
}


val cases = listOf(
listOf(9, 3, 1),
listOf(9, 1, 3),
listOf(3, 9, 1),
listOf(3, 1, 9),
listOf(1, 3, 9),
listOf(1, 9, 3)
)

fun solve() {
val n = readln().toInt()
val hps = readln().split(' ').map { it.toInt() }
val scves = Scves(hp1 = hps.first(), hp2 = hps.getOrElse(1) { 0 }, hp3 = hps.getOrElse(2) { 0 })
val queue = ArrayDeque<Pair<Scves, Int>>()
queue.add(scves to 0)

while (queue.isNotEmpty()) {
val nowHps = queue.removeFirst()
if (nowHps.first.isAllDie()) {
println(nowHps.second)
break
}
val liveCount = nowHps.first.countLive()

if (liveCount == 1) {
queue.add(
nowHps.first.copy(
hp1 = nowHps.first.hp1 - 9,
hp2 = nowHps.first.hp2 - 9,
hp3 = nowHps.first.hp3 - 9,
) to nowHps.second + 1
)
} else if (liveCount == 2) {
val (hp1, hp2) = nowHps.first.getLiveHP()
for ((case1, case2) in listOf((9 to 3), (3 to 9))) {
queue.add(
nowHps.first.copy(
hp1 = hp1 - case1,
hp2 = hp2 - case2,
hp3 = 0
) to nowHps.second + 1
)
}
} else {
for (case in cases) {
queue.add(
nowHps.first.copy(
hp1 = nowHps.first.hp1 - case[0],
hp2 = nowHps.first.hp2 - case[1],
hp3 = nowHps.first.hp3 - case[2],
) to nowHps.second + 1
)
}
}
Comment on lines +52 to +81
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이부분 코드가 예술로 예쁘다고 생각했슴다^^

}
}
}

fun main() {
뮤탈리스크().solve()
}
96 changes: 96 additions & 0 deletions src/main/kotlin/heejik/60week/스티커 재배치.kt
Original file line number Diff line number Diff line change
@@ -0,0 +1,96 @@
package heejik.`60week`

import kotlin.math.min

class `스티커 재배치` {
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오호 좋은 문제 공유 감사합니다

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문제 추천 감사합니다~~


fun solve() {
var minPrice = Int.MAX_VALUE

val (n, m, k) = readln().split(' ').map { it.toInt() }
// 각 인덱스마다 번호에 따른 알맞은 값 존재
val stickerAlpha = MutableList(size = m) { 'a' }
val stickerOut = MutableList(size = m) { 0 }
val stickerPrice = MutableList(size = m) { 0 }
val priceOfAlpha = mutableMapOf<Char, Int>()
val outOfAlpha = mutableMapOf<Char, MutableList<Int>>()

repeat(m) { id ->
val (s, d, j) = readln().split(' ')
stickerAlpha[id] = s.first()
stickerOut[id] = d.toInt()
stickerPrice[id] = j.toInt()
// 각 알파벳마다 최소 가격 리스트업
priceOfAlpha[s.first()] = min(priceOfAlpha.getOrDefault(s.first(), Int.MAX_VALUE), j.toInt())
// 각 알파벳마다 최소 떼기 비용 리스트업
outOfAlpha[s.first()]?.add(d.toInt()) ?: run { outOfAlpha[s.first()] = mutableListOf(d.toInt()) }
}
// println(outOfAlpha)
// println(outOfAlpha)
// println(cheapestPrice)

val board = readln().split(' ').map { it.toInt() - 1 }
val s = readln()

for (i in 0..board.size - s.length) {
val outOfAlphaInRange = mutableMapOf<Char, MutableList<Int>>()
for ((alpha, outPrice) in outOfAlpha) {
outOfAlphaInRange[alpha] = outPrice.toMutableList()
}
// println(outOfAlphaInRange)
var price = 0
val trash = mutableListOf<Char>()
// 먼저 쓰레기통에 다 넣는다.
for (j in i until i + s.length) {
val indexOfS = j - i
val findSticker = s[indexOfS]
val currentSticker = stickerAlpha[board[j]]
// s 의 부분과 보드판 위의 알파벳의 부분과 다르면
if (findSticker != currentSticker) {
// 현재 스티커 떼기
price += stickerOut[board[j]]
// 쓰레기통에 넣기
trash.add(currentSticker)
}
}

// 쓰레기통에 넣은 걸 기반으로 재활용 하거나 구매
for (j in i until i + s.length) {
val indexOfS = j - i
val findSticker = s[indexOfS]
val currentSticker = stickerAlpha[board[j]]
// println("$i, $j, findSticker: $findSticker, currentSticker, $currentSticker")
// s 의 부분과 보드판 위의 알파벳의 부분과 다르면
if (findSticker != currentSticker) {
// 쓰레기통에 있다면 재활용
if (findSticker in trash) {
trash.remove(findSticker)
// println("$i, $j, $price, 34343")
} else { // 쓰레기통에 없다면 해당 알파벳 최소 가격으로 구매
if (findSticker !in priceOfAlpha) {
print(-1)
return
}
if (outOfAlphaInRange[findSticker]!!.min() < priceOfAlpha[findSticker]!!) {
val minOutPrice = outOfAlphaInRange[findSticker]!!.min()
outOfAlphaInRange[findSticker]!!.remove(minOutPrice)
price += minOutPrice
} else {
price += priceOfAlpha[findSticker]!!
}
}
}
}
// println(price)
if (price < minPrice) {
minPrice = price
}
}

print(if (minPrice == Int.MAX_VALUE) -1 else minPrice)
}
}

fun main() {
`스티커 재배치`().solve()
}
50 changes: 50 additions & 0 deletions src/main/kotlin/heejik/60week/트리의 지름.kt
Original file line number Diff line number Diff line change
@@ -0,0 +1,50 @@
package heejik.`60week`

class `트리의 지름` {

fun solve() {
val n = readln().toInt()

val nodes = List(size = n + 1) { mutableListOf<Pair<Int, Int>>() }
val queue = ArrayDeque<Pair<Int, Int>>()
val visited = BooleanArray(size = n + 1)

repeat(n - 1) {
val (root, child, distance) = readln().split(' ').map { it.toInt() }

nodes[root].add(child to distance)
nodes[child].add(root to distance)
}

fun bfs(start: Int): Pair<Int, Int> {
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아예 그래프 탐색처럼도 풀 수 있었군여

visited.fill(element = false)
// 원소, 가중치
queue.add(start to 0)
visited[start] = true
var maxDis = 0
var maxNumber = 0

while (queue.isNotEmpty()) {
val (number, sumDistance) = queue.removeFirst()
nodes[number].filter { visited[it.first].not() }.forEach {
queue.add(it.first to sumDistance + it.second)
visited[it.first] = true
}
if (sumDistance > maxDis) {
maxDis = sumDistance
maxNumber = number
}
}

return maxNumber to maxDis
}

val (number, _) = bfs(1)
println(bfs(number).second)
Comment on lines +19 to +43
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오 새롭게 알아갑니다!!! 👍

}
}


fun main() {
`트리의 지름`().solve()
}