Ruby Judo submission

ruby_judo.rb

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+
+
+puts "There are 6 methods to try"
+puts "1.POWER 2.FACTORIAL 3.UNIQUES 4.COMBINATIONS 5.RECTANGLE OVERLAP 6.THE COUNTING GAME"
+puts "Which would you like to try? Please enter the name or number of the method."
+choice = gets.chomp.downcase
+
+
+
+=begin
+POWER
+	Write a method power which takes two integers (base and exponent) and 
+	returns the base raised to the power of exponent. Do not use Ruby’s ** operator for this!
+
+	> power(3,4)
+	=> 81 # (3*3*3*3)
+=end
+
+def power(base, exponent) 
+	a = base
+	(exponent-1).times{a *= base}   #exponent -1 because times starts at 0
+	return a
+end
+
+if choice == "power" || choice == "1"
+	puts "POWER"
+	puts "This will return an expoent of a number. First enter the base number."
+	base = gets.chomp.to_i
+	if base.is_a?(Integer)
+		puts "Now enter the exponent."
+		exponent = gets.chomp.to_i
+		if exponent.is_a?(Integer)	
+			answer = power(base,exponent)				
+
+			puts "The answer for a base of #{base} and an exponent of #{exponent} is #{answer}."
+		end		
+	end
+end	
+
+
+
+
+
+
+=begin
+FACTORIAL
+	Write a method factorial which takes a number and returns the product of every number 
+	up to the current number multiplied together.
+
+	> factorial(5)
+	=> 120  # from 1*2*3*4*5
+=end
+
+def factorial(b)
+	(1...b).each do |x|
+		b *= x
+	end
+	return b
+end
+
+if choice == "factorial" || choice == "2"
+	puts "FACTORIAL"
+	puts "Enter a number to get the product of very number up to it multiplied together"
+	number = gets.chomp.to_i
+	answer = factorial(number)
+	puts "Your answer is #{answer}"
+end	
+
+
+=begin
+UNIQUES
+	Write a method uniques which takes an array of items and returns the array without any duplicates. 
+	Don’t use Ruby’s uniq method!
+
+	uniques([1,5,”frog”, 2,1,3,”frog”])
+	=> [1,5,”frog”,2,3]
+=end
+def uniques(array) #converts incoming string to array
+	array.each do |x|					
+		position = array.index(x) + 1
+		while position < array.length 	
+			if x === array[position]		
+				array.delete_at(position)	#removes repeating elements
+			else 
+				position += 1
+			end
+		end	
+	end
+	return array
+end
+
+
+if choice == "uniques" || choice == "3"
+	puts "UNIQUES"
+	puts "Enter an array with repeating elements separated by commas like this : 1, 2, cat, dog, 2, cat"
+	arrays = gets.chomp
+	arrays = arrays.split(",")
+	answer = uniques(arrays)
+	puts "Here is your array with all repeating elements removed: #{answer}"
+end
+
+
+=begin
+
+COMBINATIONS
+	Write a method combinations which takes two arrays of strings and 
+	returns an array with all of the combinations of the items in them, 
+	listing the first items first.
+
+	> combinations([“on”,”in”],[“to”,”rope”])
+	=> [“onto”,”onrope”,”into”,”inrope”]
+=end
+
+def combinations(a,b)
+	new_array = []
+	a.each do |x| 				
+		b.each do |i|
+			new_string = x + i 			#adds the two string together
+			new_array << new_string
+		end
+	end
+	return new_array
+end
+
+
+if choice == "combinations" || choice == "4"
+	puts "COMBINATIONS"
+	puts "This method takes 2 lists of strings and returns a list of combinations made from them." 
+	puts "Enter a list of strings separated by commas with no spaces. Like this: on, to, my"
+	array_1 = gets.chomp
+	puts "Enter another list of string"
+	array_2 = gets.chomp
+	array_1 = array_1.split(",")
+	array_2 = array_2.split(",")
+	puts combinations(array_1, array_2)
+end
+
+
+=begin
+RECTANGLE OVERLAP
+	Write a method overlap which takes two rectangles defined by the coordinates of 
+	their corners, e.g. [[0,0],[3,3]] and [[1,1],[4,6]], and determines whether they overlap. 
+	You can assume all coordinates are positive integers.
+
+	> overlap( [ [0,0],[3,3] ], [ [1,1],[4,5] ] )
+	=> true
+	> overlap( [ [0,0],[1,4] ], [ [1,1],[3,2] ] )
+	=> false
+
+	possible solution
+
+	grid is 
+
+	1a		1b
+	xy		xy
+
+
+	2a		2b
+	xy		xy
+
+	if both 2b x and y is greater than 1a x and y = overlap
+		or
+	if 1b x is greater than 2a x = overlap
+=end
+
+def rectangle_overlap (*c)
+	c = c[0]
+	#Box 1 coordinates
+	a1 = [*c[0], *c[1]] 	#Box 1 bottom left corner coordinates.
+	b1 = [*c[2], *c[3]]		#Box 1 top right corner coordinate.
+	a2 = [*c[4], *c[5]]		#Box 2 bottom left corner coordinate.	
+	b2 = [*c[6], *c[7]]		#Box 2 bottom top right coordinate.
+	puts "c #{c}"
+	if (a1[0] < b2[0]) && (a1[1]) < (b2[1]) && (b1[0] > a2[0]) && (b1[1] > a2[1]) # tests if coordinates overlap
+
+		return "Your rectangles overlap!"
+	else
+		return "No overlap"
+	end
+end
+
+if choice == "rectangle overlap" || choice == "5"
+	puts "This method checks if 2 rectangles overlap on a grid. You will need to enter 8 numbers for the bottom left and top right coordinates for both rectangles"
+	puts "Here I would add a better mechanism for getting the coordinates, but I don't want to spend more time on this problem"
+	coordinates = []
+	until coordinates.length == 8 do		
+		puts "Please add the coodinate"
+		input = gets.chomp.to_i
+		coordinates << input
+	end
+	puts rectangle_overlap (coordinates)
+end
+
+=begin
+THE COUNTING GAME
+	Let's take on a more challenging logic problem. Remember the counting game that you 
+	pseudocoded during the Pseudocoding Assignment? For a recap:
+
+	10 friends are sitting in a circle around a table and decide to play a new game. 
+	In it, they count up through the numbers from 1 to 100. The first person says "1", 
+	the second says "2" and so on... but with a few catches:
+
+	Whenever the number is divisible by 7, they switch directions. So person 6 will say "6", 
+	person 7 will say "7", then person 6 again will say "8".
+	Whenever the number is divisible by 11, they skip the next person for the following number. 
+	For instance, if person 3 says "33", person 5 will say "34" instead (person 4 gets skipped).
+	Your job is to code a program which outputs each number and which person said it. 
+	Use it to show that player 1 will say the number "100".
+
+	Tips:
+
+	Remember to stick with brute force instead of trying to "figure out" the trick to the problem.
+	Name your variables well!
+	Ignore the skipping to start out with. Only add it when you're ready.
+	Make your method take two inputs -- the number of players and the number you're counting up to. 
+	Then see who says the last number each time!
+=end
+
+def counting(players, number)
+	player_position = 1
+	count = 1
+	x = 1
+	until count == number do
+		if count % 7
+			x = - 1
+		elsif count % 11
+			x = 2 * x
+		else 
+			x = x
+		end
+		count += 1
+		player_position = player_position + x
+			if player_position == players + 1
+				player_position = 1
+			elsif player_position == players + 2
+				player_position = 2
+			elsif player_position == -1
+				player_position == players
+			elsif player_position == -2
+				player_position = players - 1
+			end
+	end
+	puts "The last player is #{player_position}"
+end
+
+if choice == "the counting game" || choice == "6"
+	puts "This method plays the counting game!!!"
+	puts "How many players are there?"
+	players = gets.chomp.to_i
+	puts "What number are they counting to?"
+	num = gets.chomp.to_i
+	puts counting(players, num)
+end