[Hacker Rank]: Day of the Programmer partial doc moved as Markdown

src/hackerrank/implementation/dayOfProgrammer.md

@@ -0,0 +1,117 @@
+# [Day of the Programmer](https://www.hackerrank.com/challenges/day-of-the-programmer)
+
+Difficulty: #easy
+Category: #implementation
+
+Marie invented a [Time Machine](https://en.wikipedia.org/wiki/Time_machine)
+and wants to test it by time-traveling to visit Russia on the
+[Day of the Programmer](https://en.wikipedia.org/wiki/Day_of_the_Programmer)
+(the 256th day of the year) during a year in the inclusive range from 1700
+to 2700.
+
+From 1700 to 1917, Russia's official calendar was the
+[Julian calendar](https://en.wikipedia.org/wiki/Julian_calendar); since 1919
+they used the
+[Gregorian calendar](https://en.wikipedia.org/wiki/Gregorian_calendar)
+system. The transition from the Julian to Gregorian calendar system occurred
+in 1918, when the next day after January 31st was February 14th. This means
+that in 1918, February 14th was the 32nd day of the year in Russia.
+
+In both calendar systems, February is the only month with a variable amount
+of days; it has 29 days during a leap year, and 28 days during all other
+years. In the Julian calendar, leap years are divisible by 4; in the
+Gregorian calendar, leap years are either of the following:
+
+- Divisible by 400.
+- Divisible by 4 and not divisible by 100.
+
+Given a year, $ y $, find the date of the 256th day of that year according to
+the official Russian calendar during that year. Then print it in the format
+$ dd.mm.yyyy $, where $ dd $ is the two-digit day, mm is the two-digit month, and
+$ yyyy $ is $ y $.
+
+For example, the given $ year = 1984 $. 1984 is divisible by 4, so it is a leap
+year. The 256th day of a leap year after 1918 is September 12, so the answer
+is $ 12.09.1984 $.
+
+## Function Description
+
+Complete the dayOfProgrammer function in the editor below. It should return
+a string representing the date of the 256th day of the year given.
+
+dayOfProgrammer has the following parameter(s):
+
+- year: an integer
+
+## Input Format
+
+A single integer denoting year $ y $.
+
+## Constraints
+
+- $ 1700 < y < 2700 $
+
+## Output Format
+
+Print the full date of Day of the Programmer during year y in the format
+dd.mm.yyyy, where dd is the two-digit day, mm is the two-digit month, and
+yyyy is y.
+
+## Sample Input 0
+
+```text
+2017
+```
+
+## Sample Output 0
+
+```text
+13.09.2017
+```
+
+## Explanation 0
+
+In the year $ y = 2017 $, January has 31 days, February has 28 days, March has
+31 days, April has 30 days, May has 31 days, June has 30 days, July has 31
+days, and August has 31 days. When we sum the total number of days in the
+first eight months, we get $ 31 + 28 + 31 + 30 + 31 + 30 + 31 + 31 = 243 $.
+Day of the Programmer is the 256th day, so then calculate $ 256 - 243 = 13 $
+to determine that it falls on day 13 of the 9th month (September). We then
+print the full date in the specified format, which is $ 13.09.2017 $.
+
+## Sample Input 1
+
+```text
+2016
+```
+
+## Sample Output 1
+
+```text
+12.09.2016
+```
+
+Year $ y = 2016 $ is a leap year, so February has 29 days but all the other
+months have the same number of days as in 2017. When we sum the total
+number of days in the first eight months, we get
+$ 31 + 29 + 31 + 30 + 31 + 30 + 31 + 31 = 244 $.
+Day of the Programmer is the 256th day, so then
+calculate $ 256 - 244 = 12 $ to determine that it falls on day 12 of the 9th
+month (September). We then print the full date in the specified format,
+which is $ 12.09.2016 $.
+
+## Sample Input 2
+
+```text
+1800
+```
+
+## Sample Output 2
+
+```text
+12.09.1800
+```
+
+## Explanation 2
+
+Since 1800 is leap year as per Julian calendar. Day lies on 12 September.

src/hackerrank/implementation/dayOfProgrammer.ts

@@ -1,109 +1,3 @@
-/**
- * Bill Division
- *
- * https://www.hackerrank.com/challenges/bon-appetit
- *
- * Difficulty: #easy
- * Category: #implementation
- *
- * Marie invented a [Time Machine](https://en.wikipedia.org/wiki/Time_machine)
- * and wants to test it by time-traveling to visit Russia on the
- * [Day of the Programmer](https://en.wikipedia.org/wiki/Day_of_the_Programmer)
- * (the 256th day of the year) during a year in the inclusive range from 1700
- * to 2700.
- *
- * From 1700 to 1917, Russia's official calendar was the
- * [Julian calendar](https://en.wikipedia.org/wiki/Julian_calendar); since 1919
- * they used the
- * [Gregorian calendar](https://en.wikipedia.org/wiki/Gregorian_calendar)
- * system. The transition from the Julian to Gregorian calendar system occurred
- * in 1918, when the next day after January 31st was February 14th. This means
- * that in 1918, February 14th was the 32nd day of the year in Russia.
- *
- * In both calendar systems, February is the only month with a variable amount
- * of days; it has 29 days during a leap year, and 28 days during all other
- * years. In the Julian calendar, leap years are divisible by 4; in the
- * Gregorian calendar, leap years are either of the following:
- *
- * * Divisible by 400.
- * * Divisible by 4 and not divisible by 100.
- *
- * Given a year, y, find the date of the 256th day of that year according to
- * the official Russian calendar during that year. Then print it in the format
- * dd.mm.yyyy, where dd is the two-digit day, mm is the two-digit month, and
- * yyyy is y.
- *
- * For example, the given year = 1984. 1984 is divisible by 4, so it is a leap
- * year. The 256th day of a leap year after 1918 is September 12, so the answer
- * is 12.09.1984.
- *
- * # Function Description
- * Complete the dayOfProgrammer function in the editor below. It should return
- * a string representing the date of the 256th day of the year given.
- *
- * dayOfProgrammer has the following parameter(s):
- * * year: an integer
- *
- * # Input Format
- * A single integer denoting year y.
- *
- * # Constraints
- * * 1700 < y < 2700
- *
- * # Output Format
- * Print the full date of Day of the Programmer during year y in the format
- * dd.mm.yyyy, where dd is the two-digit day, mm is the two-digit month, and
- * yyyy is y.
- *
- * # Sample Input 0
- * ```
- * 2017
- * ```
- * Sample Output 0
- * ```
- * 13.09.2017
- * ```
- *
- * # Explanation 0
- * In the year y = 2017, January has 31 days, February has 28 days, March has
- * 31 days, April has 30 days, May has 31 days, June has 30 days, July has 31
- * days, and August has 31 days. When we sum the total number of days in the
- * first eight months, we get 31 + 28 + 31 + 30 + 31 + 30 + 31 + 31 = 243.
- * Day of the Programmer is the 256th day, so then calculate 256 - 243 = 13
- * to determine that it falls on day 13 of the 9th month (September). We then
- * print the full date in the specified format, which is 13.09.2017.
- *
- * # Sample Input 1
- * ```
- * 2016
- * ```
- *
- * # Sample Output 1
- * ```
- * 12.09.2016
- * ```
- * Year y = 2016 is a leap year, so February has 29 days but all the other
- * months have the same number of days as in 2017. When we sum the total
- * number of days in the first eight months, we get 31 + 29 + 31 + 30 + 31
- * + 30 + 31 + 31 = 244. Day of the Programmer is the 256th day, so then
- * calculate 256 - 244 = 12 to determine that it falls on day 12 of the 9th
- * month (September). We then print the full date in the specified format,
- * which is 12.09.2016.
- *
- * # Sample Input 2
- * ```
- * 1800
- * ```
- *
- * # Sample Output 2
- * ```
- * 12.09.1800
- * ```
- *
- * # Explanation 2
- * Since 1800 is leap year as per Julian calendar. Day lies on 12 September.
- */
-
 import { logger as console } from '../../logger';
 import { MonthNumbers, daysInMonthNumber } from '../../constants';