Update 1.md

mids-w203 · Jan 6, 2024 · cc1caea · cc1caea
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diff --git a/_problems/unit-02/A-computing-the-distribution-induced-by-a-random-variable/1.md b/_problems/unit-02/A-computing-the-distribution-induced-by-a-random-variable/1.md
@@ -47,8 +47,8 @@ $$
 or
 
 $$
-P(X = 2) = P(Y = 3 \cup Y = 4 \cup Y = 5 \cup Y = 6)  = \text{ (Independence) } P(Y = 3) + P(Y = 4) +  P(Y = 5) P(Y = 6) = 
-\frac{1}{6} + \frac{1}{6} + \frac{1}{6} + \frac{1}{6}= \frac{2}{3}
+P(X = 2) = P(Y = 3 \cup Y = 4 \cup Y = 5 \cup Y = 6)  = \text{ (Independence) } P(Y = 3) + P(Y = 4) +  P(Y = 5) P(Y = 6) \\
+= \frac{1}{6} + \frac{1}{6} + \frac{1}{6} + \frac{1}{6}= \frac{2}{3}
 $$
 
 The PMF of X is