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Use last element as end time #58
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Original file line number | Diff line number | Diff line change |
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@@ -614,7 +614,7 @@ def envelope(self) -> tuple[datetime, datetime]: | |
end = datetime.min | ||
for s, e in self._start_include + self._startend_include + self._end_include: | ||
start = min(start, s) | ||
end = max(end, s) | ||
end = max(end, e) | ||
There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. Thanks, very well that you also included a test. |
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if end < start: | ||
raise TimeBoundsException( | ||
f"TimeBoundsEnvelope end < start: {end} < {start}" | ||
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Original file line number | Diff line number | Diff line change |
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@@ -0,0 +1,11 @@ | ||
from datetime import datetime | ||
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from pyaro.timeseries.Filter import TimeBoundsFilter | ||
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def test_timemax(): | ||
bounds = TimeBoundsFilter(start_include=[("2023-01-01 00:00:00", "2024-01-01 00:00:00")]) | ||
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envelope = bounds.envelope() | ||
assert envelope[0] == datetime.fromisoformat("2023-01-01 00:00:00") | ||
assert envelope[1] == datetime.fromisoformat("2024-01-01 00:00:00") |
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Is this the cleanest way to set the
start
/end
Also, why is does
start
depends onself._end_include
andend
depends onself._start_include
?maybe itertools.chain can improve the readability
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I don't think the chain-version is very readable here.
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Yes, at the cost of creating new lists this could be written on a simpler way
In any case, my question still stands
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The tuple values of (start, end) are the time-ranges of the filter, while start_include/end_include refer to measurements starttime/endtime.