swapping vars without temp var

[gk3000]

Swapping 2 values without temp variable

TL;DR;

With array destructuring it's really easy to swap two values in a single expression without need of a temporary variable.

let foo = 10, bar = 5;
[foo, bar] = [bar, foo]

That's it, now foo is 5 and bar is 10.

JS first evaluates newly created array on the right of the assignment operator and then destructures it according to the order of vars on the left and since they are the same but in reverse order their values are swapped.

Works for array's items as well:

let foo = [1,2,3,4,5];
[foo[0], foo[4]] = [foo[4],foo[0]]

And objects:

let foo = {a:1,b:2,c:3};
[foo.a,foo.b]=[foo.b,foo.a]

👻

@gk3000

Extra

[dhbalaji]

[zenopopovici]

@dhbalaji Add tip 75 and add it to the readme.