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[feat] add ruby code - chapter dynamic programming
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37 changes: 37 additions & 0 deletions
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codes/ruby/chapter_dynamic_programming/climbing_stairs_backtrack.rb
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=begin | ||
File: climbing_stairs_backtrack.rb | ||
Created Time: 2024-05-29 | ||
Author: Xuan Khoa Tu Nguyen ([email protected]) | ||
=end | ||
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### 回溯 ### | ||
def backtrack(choices, state, n, res) | ||
# 当爬到第 n 阶时,方案数量加 1 | ||
res[0] += 1 if state == n | ||
# 遍历所有选择 | ||
for choice in choices | ||
# 剪枝:不允许越过第 n 阶 | ||
next if state + choice > n | ||
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# 尝试:做出选择,更新状态 | ||
backtrack(choices, state + choice, n, res) | ||
end | ||
# 回退 | ||
end | ||
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### 爬楼梯:回溯 ### | ||
def climbing_stairs_backtrack(n) | ||
choices = [1, 2] # 可选择向上爬 1 阶或 2 阶 | ||
state = 0 # 从第 0 阶开始爬 | ||
res = [0] # 使用 res[0] 记录方案数量 | ||
backtrack(choices, state, n, res) | ||
res.first | ||
end | ||
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### Driver Code ### | ||
if __FILE__ == $0 | ||
n = 9 | ||
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res = climbing_stairs_backtrack(n) | ||
puts "爬 #{n} 阶楼梯共有 #{res} 种方案" | ||
end |
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codes/ruby/chapter_dynamic_programming/climbing_stairs_constraint_dp.rb
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=begin | ||
File: climbing_stairs_constraint_dp.rb | ||
Created Time: 2024-05-29 | ||
Author: Xuan Khoa Tu Nguyen ([email protected]) | ||
=end | ||
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### 带约束爬楼梯:动态规划 ### | ||
def climbing_stairs_backtrack(n) | ||
return 1 if n == 1 || n == 2 | ||
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# 初始化 dp 表,用于存储子问题的解 | ||
dp = Array.new(n + 1) { Array.new(3, 0) } | ||
# 初始状态:预设最小子问题的解 | ||
dp[1][1], dp[1][2] = 1, 0 | ||
dp[2][1], dp[2][2] = 0, 1 | ||
# 状态转移:从较小子问题逐步求解较大子问题 | ||
for i in 3...(n + 1) | ||
dp[i][1] = dp[i - 1][2] | ||
dp[i][2] = dp[i - 2][1] + dp[i - 2][2] | ||
end | ||
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dp[n][1] + dp[n][2] | ||
end | ||
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### Driver Code ### | ||
if __FILE__ == $0 | ||
n = 9 | ||
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res = climbing_stairs_backtrack(n) | ||
puts "爬 #{n} 阶楼梯共有 #{res} 种方案" | ||
end |
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codes/ruby/chapter_dynamic_programming/climbing_stairs_dfs.rb
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=begin | ||
File: climbing_stairs_dfs.rb | ||
Created Time: 2024-05-29 | ||
Author: Xuan Khoa Tu Nguyen ([email protected]) | ||
=end | ||
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### 搜索 ### | ||
def dfs(i) | ||
# 已知 dp[1] 和 dp[2] ,返回之 | ||
return i if i == 1 || i == 2 | ||
# dp[i] = dp[i-1] + dp[i-2] | ||
dfs(i - 1) + dfs(i - 2) | ||
end | ||
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### 爬楼梯:搜索 ### | ||
def climbing_stairs_dfs(n) | ||
dfs(n) | ||
end | ||
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### Driver Code ### | ||
if __FILE__ == $0 | ||
n = 9 | ||
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res = climbing_stairs_dfs(n) | ||
puts "爬 #{n} 阶楼梯共有 #{res} 种方案" | ||
end |
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codes/ruby/chapter_dynamic_programming/climbing_stairs_dfs_mem.rb
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=begin | ||
File: climbing_stairs_dfs_mem.rb | ||
Created Time: 2024-05-29 | ||
Author: Xuan Khoa Tu Nguyen ([email protected]) | ||
=end | ||
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### 记忆化搜索 ### | ||
def dfs(i, mem) | ||
# 已知 dp[1] 和 dp[2] ,返回之 | ||
return i if i == 1 || i == 2 | ||
# 若存在记录 dp[i] ,则直接返回之 | ||
return mem[i] if mem[i] != -1 | ||
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# dp[i] = dp[i-1] + dp[i-2] | ||
count = dfs(i - 1, mem) + dfs(i - 2, mem) | ||
# 记录 dp[i] | ||
mem[i] = count | ||
end | ||
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### 爬楼梯:记忆化搜索 ### | ||
def climbing_stairs_dfs_mem(n) | ||
# mem[i] 记录爬到第 i 阶的方案总数,-1 代表无记录 | ||
mem = Array.new(n + 1, -1) | ||
dfs(n, mem) | ||
end | ||
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### Driver Code ### | ||
if __FILE__ == $0 | ||
n = 9 | ||
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res = climbing_stairs_dfs_mem(n) | ||
puts "爬 #{n} 阶楼梯共有 #{res} 种方案" | ||
end |
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codes/ruby/chapter_dynamic_programming/climbing_stairs_dp.rb
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=begin | ||
File: climbing_stairs_dp.rb | ||
Created Time: 2024-05-29 | ||
Author: Xuan Khoa Tu Nguyen ([email protected]) | ||
=end | ||
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### 爬楼梯:动态规划 ### | ||
def climbing_stairs_dp(n) | ||
return n if n == 1 || n == 2 | ||
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# 初始化 dp 表,用于存储子问题的解 | ||
dp = Array.new(n + 1, 0) | ||
# 初始状态:预设最小子问题的解 | ||
dp[1], dp[2] = 1, 2 | ||
# 状态转移:从较小子问题逐步求解较大子问题 | ||
(3...(n + 1)).each { |i| dp[i] = dp[i - 1] + dp[i - 2] } | ||
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dp[n] | ||
end | ||
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### 爬楼梯:空间优化后的动态规划 ### | ||
def climbing_stairs_dp_comp(n) | ||
return n if n == 1 || n == 2 | ||
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a, b = 1, 2 | ||
(3...(n + 1)).each { a, b = b, a + b } | ||
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b | ||
end | ||
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### Driver Code ### | ||
if __FILE__ == $0 | ||
n = 9 | ||
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res = climbing_stairs_dp(n) | ||
puts "爬 #{n} 阶楼梯共有 #{res} 种方案" | ||
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res = climbing_stairs_dp_comp(n) | ||
puts "爬 #{n} 阶楼梯共有 #{res} 种方案" | ||
end |
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=begin | ||
File: coin_change.rb | ||
Created Time: 2024-05-29 | ||
Author: Xuan Khoa Tu Nguyen ([email protected]) | ||
=end | ||
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### 零钱兑换:动态规划 ### | ||
def coin_change_dp(coins, amt) | ||
n = coins.length | ||
_MAX = amt + 1 | ||
# 初始化 dp 表 | ||
dp = Array.new(n + 1) { Array.new(amt + 1, 0) } | ||
# 状态转移:首行首列 | ||
(1...(amt + 1)).each { |a| dp[0][a] = _MAX } | ||
# 状态转移:其余行和列 | ||
for i in 1...(n + 1) | ||
for a in 1...(amt + 1) | ||
if coins[i - 1] > a | ||
# 若超过目标金额,则不选硬币 i | ||
dp[i][a] = dp[i - 1][a] | ||
else | ||
# 不选和选硬币 i 这两种方案的较小值 | ||
dp[i][a] = [dp[i - 1][a], dp[i][a - coins[i - 1]] + 1].min | ||
end | ||
end | ||
end | ||
dp[n][amt] != _MAX ? dp[n][amt] : -1 | ||
end | ||
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### 零钱兑换:空间优化后的动态规划 ### | ||
def coin_change_dp_comp(coins, amt) | ||
n = coins.length | ||
_MAX = amt + 1 | ||
# 初始化 dp 表 | ||
dp = Array.new(amt + 1, _MAX) | ||
dp[0] = 0 | ||
# 状态转移 | ||
for i in 1...(n + 1) | ||
# 正序遍历 | ||
for a in 1...(amt + 1) | ||
if coins[i - 1] > a | ||
# 若超过目标金额,则不选硬币 i | ||
dp[a] = dp[a] | ||
else | ||
# 不选和选硬币 i 这两种方案的较小值 | ||
dp[a] = [dp[a], dp[a - coins[i - 1]] + 1].min | ||
end | ||
end | ||
end | ||
dp[amt] != _MAX ? dp[amt] : -1 | ||
end | ||
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### Driver Code ### | ||
if __FILE__ == $0 | ||
coins = [1, 2, 5] | ||
amt = 4 | ||
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# 动态规划 | ||
res = coin_change_dp(coins, amt) | ||
puts "凑到目标金额所需的最少硬币数量为 #{res}" | ||
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# 空间优化后的动态规划 | ||
res = coin_change_dp_comp(coins, amt) | ||
puts "凑到目标金额所需的最少硬币数量为 #{res}" | ||
end |
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=begin | ||
File: coin_change_ii.rb | ||
Created Time: 2024-05-29 | ||
Author: Xuan Khoa Tu Nguyen ([email protected]) | ||
=end | ||
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### 零钱兑换 II:动态规划 ### | ||
def coin_change_ii_dp(coins, amt) | ||
n = coins.length | ||
# 初始化 dp 表 | ||
dp = Array.new(n + 1) { Array.new(amt + 1, 0) } | ||
# 初始化首列 | ||
(0...(n + 1)).each { |i| dp[i][0] = 1 } | ||
# 状态转移 | ||
for i in 1...(n + 1) | ||
for a in 1...(amt + 1) | ||
if coins[i - 1] > a | ||
# 若超过目标金额,则不选硬币 i | ||
dp[i][a] = dp[i - 1][a] | ||
else | ||
# 不选和选硬币 i 这两种方案之和 | ||
dp[i][a] = dp[i - 1][a] + dp[i][a - coins[i - 1]] | ||
end | ||
end | ||
end | ||
dp[n][amt] | ||
end | ||
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### 零钱兑换 II:空间优化后的动态规划 ### | ||
def coin_change_ii_dp_comp(coins, amt) | ||
n = coins.length | ||
# 初始化 dp 表 | ||
dp = Array.new(amt + 1, 0) | ||
dp[0] = 1 | ||
# 状态转移 | ||
for i in 1...(n + 1) | ||
# 正序遍历 | ||
for a in 1...(amt + 1) | ||
if coins[i - 1] > a | ||
# 若超过目标金额,则不选硬币 i | ||
dp[a] = dp[a] | ||
else | ||
# 不选和选硬币 i 这两种方案之和 | ||
dp[a] = dp[a] + dp[a - coins[i - 1]] | ||
end | ||
end | ||
end | ||
dp[amt] | ||
end | ||
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### Driver Code ### | ||
if __FILE__ == $0 | ||
coins = [1, 2, 5] | ||
amt = 5 | ||
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# 动态规划 | ||
res = coin_change_ii_dp(coins, amt) | ||
puts "凑出目标金额的硬币组合数量为 #{res}" | ||
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# 空间优化后的动态规划 | ||
res = coin_change_ii_dp_comp(coins, amt) | ||
puts "凑出目标金额的硬币组合数量为 #{res}" | ||
end |
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