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fix: corrected bug that prevented combined fits with multiple x-obs i…
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…n some cases (fjosw#241)

* fix: corrected bug that prevented combined fits with multiple x-obs in some cases

* made test more complex

* [Fix] Slightly increase tolerance for matrix function test.

* Adapt test_merge_idx to compare lists

---------

Co-authored-by: Simon Kuberski <[email protected]>
Co-authored-by: Fabian Joswig <[email protected]>
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3 people authored Sep 13, 2024
1 parent 1d6f7f6 commit 4b1bb08
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Showing 4 changed files with 21 additions and 7 deletions.
2 changes: 1 addition & 1 deletion pyerrors/fits.py
Original file line number Diff line number Diff line change
Expand Up @@ -256,7 +256,7 @@ def func_b(a, x):
if sorted(list(funcd.keys())) != key_ls:
raise ValueError('x and func dictionaries do not contain the same keys.')

x_all = np.concatenate([np.array(xd[key]) for key in key_ls])
x_all = np.concatenate([np.array(xd[key]).transpose() for key in key_ls]).transpose()
y_all = np.concatenate([np.array(yd[key]) for key in key_ls])

y_f = [o.value for o in y_all]
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14 changes: 14 additions & 0 deletions tests/fits_test.py
Original file line number Diff line number Diff line change
Expand Up @@ -1082,6 +1082,20 @@ def test_combined_resplot_qqplot():
fr = pe.least_squares(xd, yd, fd, resplot=True, qqplot=True)
plt.close('all')

def test_combined_fit_xerr():
fitd = {
'a' : lambda p, x: p[0] * x[0] + p[1] * x[1],
'b' : lambda p, x: p[0] * x[0] + p[2] * x[1],
'c' : lambda p, x: p[0] * x[0] + p[3] * x[1],
}
yd = {
'a': [pe.cov_Obs(3 + .1 * np.random.uniform(), .1**2, 'a' + str(i)) for i in range(5)],
'b': [pe.cov_Obs(1 + .1 * np.random.uniform(), .1**2, 'b' + str(i)) for i in range(6)],
'c': [pe.cov_Obs(3 + .1 * np.random.uniform(), .1**2, 'c' + str(i)) for i in range(3)],
}
xd = {k: np.transpose([[1 + .01 * np.random.uniform(), 2] for i in range(len(yd[k]))]) for k in fitd}
pe.fits.least_squares(xd, yd, fitd)


def test_x_multidim_fit():
x1 = np.arange(1, 10)
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6 changes: 3 additions & 3 deletions tests/linalg_test.py
Original file line number Diff line number Diff line change
Expand Up @@ -276,10 +276,10 @@ def test_matrix_functions():
for (i, j), entry in np.ndenumerate(check_inv):
entry.gamma_method()
if(i == j):
assert math.isclose(entry.value, 1.0, abs_tol=1e-9), 'value ' + str(i) + ',' + str(j) + ' ' + str(entry.value)
assert math.isclose(entry.value, 1.0, abs_tol=2e-9), 'value ' + str(i) + ',' + str(j) + ' ' + str(entry.value)
else:
assert math.isclose(entry.value, 0.0, abs_tol=1e-9), 'value ' + str(i) + ',' + str(j) + ' ' + str(entry.value)
assert math.isclose(entry.dvalue, 0.0, abs_tol=1e-9), 'dvalue ' + str(i) + ',' + str(j) + ' ' + str(entry.dvalue)
assert math.isclose(entry.value, 0.0, abs_tol=2e-9), 'value ' + str(i) + ',' + str(j) + ' ' + str(entry.value)
assert math.isclose(entry.dvalue, 0.0, abs_tol=2e-9), 'dvalue ' + str(i) + ',' + str(j) + ' ' + str(entry.dvalue)

# Check Cholesky decomposition
sym = np.dot(matrix, matrix.T)
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6 changes: 3 additions & 3 deletions tests/obs_test.py
Original file line number Diff line number Diff line change
Expand Up @@ -554,11 +554,11 @@ def test_merge_idx():

for j in range(5):
idll = [range(1, int(round(np.random.uniform(300, 700))), int(round(np.random.uniform(1, 14)))) for i in range(10)]
assert pe.obs._merge_idx(idll) == sorted(set().union(*idll))
assert list(pe.obs._merge_idx(idll)) == sorted(set().union(*idll))

for j in range(5):
idll = [range(int(round(np.random.uniform(1, 28))), int(round(np.random.uniform(300, 700))), int(round(np.random.uniform(1, 14)))) for i in range(10)]
assert pe.obs._merge_idx(idll) == sorted(set().union(*idll))
assert list(pe.obs._merge_idx(idll)) == sorted(set().union(*idll))

idl = [list(np.arange(1, 14)) + list(range(16, 100, 4)), range(4, 604, 4), [2, 4, 5, 6, 8, 9, 12, 24], range(1, 20, 1), range(50, 789, 7)]
new_idx = pe.obs._merge_idx(idl)
Expand Down Expand Up @@ -1457,4 +1457,4 @@ def test_missing_replica():

for op in [[O1O2, O1O2b], [O1O2O3, O1O2O3b]]:
assert np.isclose(op[1].value, op[0].value)
assert np.isclose(op[1].dvalue, op[0].dvalue, atol=0, rtol=5e-2)
assert np.isclose(op[1].dvalue, op[0].dvalue, atol=0, rtol=5e-2)

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