Skip to content
New issue

Have a question about this project? Sign up for a free GitHub account to open an issue and contact its maintainers and the community.

Sign up for GitHub

By clicking “Sign up for GitHub”, you agree to our terms of service and privacy statement. We’ll occasionally send you account related emails.

Already on GitHub? Sign in to your account

Jump to bottom

[Ch-01] Case when k is equal to the order of the set #180

Open
wants to merge 1 commit into
base: master
Choose a base branch
from
Open

[Ch-01] Case when k is equal to the order of the set #180

Changes from all commits
Commits
Show all changes
1 commit
Select commit
File filter

Filter by extension

Filter by extension
Conversations
Failed to load comments.
Loading
Jump to
Jump to file
Failed to load files.
Loading
Diff view
Diff view
2 changes: 1 addition & 1 deletion ch01.asciidoc
View file
Open in desktop
Original file line number Diff line number Diff line change
Expand Up @@ -509,7 +509,7 @@ include::code-ch01/answers.py[tag=exercise5,indent=0]
[NOTE]
====
The answer to Exercise 5 is why we choose to use finite fields with a _prime_ number of elements.
No matter what _k_ you choose, as long as it's greater than 0, multiplying the entire set by _k_ will result in the same set as you started with.
No matter what _k_ you choose, as long as it's greater than 0 (and different from the order of the set), multiplying the entire set by _k_ will result in the same set as you started with.

Intuitively, the fact that we have a prime order results in every element of a finite field being equivalent.
If the order of the set was a composite number, multiplying the set by one of the divisors would result in a smaller set.
Expand Down