The cryptopals.com Crypto Challenges
Nice introductory can be found here.
Unless specified, I've solved these using Rust.
The string:
49276d206b696c6c696e6720796f757220627261696e206c696b65206120706f69736f6e6f7573206d757368726f6f6d
Should produce:
SSdtIGtpbGxpbmcgeW91ciBicmFpbiBsaWtlIGEgcG9pc29ub3VzIG11c2hyb29t
So go ahead and make that happen. You'll need to use this code for the rest of the exercises.
Cryptopals Rule: Always operate on raw bytes, never on encoded strings. Only use hex and base64 for pretty-printing.
Write a function that takes two equal-length buffers and produces their XOR combination.
If your function works properly, then when you feed it the string:
1c0111001f010100061a024b53535009181c
... after hex decoding, and when XOR'd against:
686974207468652062756c6c277320657965
... should produce:
746865206b696420646f6e277420706c6179
The hex encoded string:
1b37373331363f78151b7f2b783431333d78397828372d363c78373e783a393b3736
... has been XOR'd against a single character. Find the key, decrypt the message.
You can do this by hand. But don't: write code to do it for you.
How? Devise some method for "scoring" a piece of English plaintext. Character frequency is a good metric. Evaluate each output and choose the one with the best score.
One of the 60-character strings in this file has been encrypted by single-character XOR.
Find it.
(Your code from #3 should help.)
Here is the opening stanza of an important work of the English language:
Burning 'em, if you ain't quick and nimble
I go crazy when I hear a cymbal
Encrypt it, under the key "ICE", using repeating-key XOR.
In repeating-key XOR, you'll sequentially apply each byte of the key; the first byte of plaintext will be XOR'd against I, the next C, the next E, then I again for the 4th byte, and so on.
It should come out to:
0b3637272a2b2e63622c2e69692a23693a2a3c6324202d623d63343c2a26226324272765272
a282b2f20430a652e2c652a3124333a653e2b2027630c692b20283165286326302e27282f
Encrypt a bunch of stuff using your repeating-key XOR function. Encrypt your mail. Encrypt your password file. Your .sig file. Get a feel for it. I promise, we aren't wasting your time with this.
There's a file here. It's been base64'd after being encrypted with repeating-key XOR.
Decrypt it.
Here's how:
- Let KEYSIZE be the guessed length of the key; try values from 2 to (say) 40.
- Write a function to compute the edit distance/Hamming distance between two strings. The Hamming distance is just the number of differing bits. The distance between:
this is a test
and
wokka wokka!!!
is 37. Make sure your code agrees before you proceed.
- For each KEYSIZE, take the first KEYSIZE worth of bytes, and the second KEYSIZE worth of bytes, and find the edit distance between them. Normalize this result by dividing by KEYSIZE.
- The KEYSIZE with the smallest normalized edit distance is probably the key. You could proceed perhaps with the smallest 2-3 KEYSIZE values. Or take 4 KEYSIZE blocks instead of 2 and average the distances.
- Now that you probably know the KEYSIZE: break the ciphertext into blocks of KEYSIZE length.
- Now transpose the blocks: make a block that is the first byte of every block, and a block that is the second byte of every block, and so on.
- Solve each block as if it was single-character XOR. You already have code to do this.
- For each block, the single-byte XOR key that produces the best looking histogram is the repeating-key XOR key byte for that block. Put them together and you have the key.
The Base64-encoded content in this file has been encrypted via AES-128 in ECB mode under the key
"YELLOW SUBMARINE".
(case-sensitive, without the quotes; exactly 16 characters; I like "YELLOW SUBMARINE" because it's exactly 16 bytes long, and now you do too).
Decrypt it. You know the key, after all.
Easiest way: use OpenSSL::Cipher and give it AES-128-ECB as the cipher.
In this file are a bunch of hex-encoded ciphertexts.
One of them has been encrypted with ECB.
Detect it.
Remember that the problem with ECB is that it is stateless and deterministic; the same 16 byte plaintext block will always produce the same 16 byte ciphertext.