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problem 2396
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hummingbird-12 committed Dec 19, 2020
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107 changes: 107 additions & 0 deletions Solutions/2396_같은 길이 막대기 만들기.cpp
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#include <cassert>
#include <cctype>
#include <climits>
#include <cmath>
#include <cstdio>
#include <cstdlib>
#include <cstring>
#include <ctime>

#include <algorithm>
#include <array>
#include <bitset>
#include <deque>
#include <functional>
#include <iomanip>
#include <iostream>
#include <iterator>
#include <limits>
#include <list>
#include <map>
#include <numeric>
#include <queue>
#include <set>
#include <sstream>
#include <stack>
#include <string>
#include <unordered_map>
#include <vector>

using namespace std;

bool skip; // Flag for quick return from backtracking's pruning

void backtracking(
vector<int>& count, // Count of sticks per length
const int largest, // The largest length
const int n, // Number of sticks
const int target, // The possible answer to be tested
int sum = 0, // Sum of lengths for current partition
int cnt = 0, // Count of sticks used
int last = 50 // The length of last stick used
) {
if (sum == target && cnt == n) {
// Answer found, print and exit right away
cout << target << '\n';
exit(0);
}
if (sum == target) {
// A partition is complete, start a new partition
sum = 0;
last = largest;
}

// [Pruning 4] To avoid duplicate chekcing, fill the rest of partition with only equal length or smaller sticks
// [Pruning 5] The possible sticks to choose are of length <= `target - sum`
for (int len = min(last, target - sum); len >= 1; len--) {
if (count[len] > 0) {
count[len]--;
backtracking(count, largest, n, target, sum + len, cnt + 1, len);
count[len]++;
if (skip) {
// Non-promising case
return;
}
// [Pruning 6] Failed to make a new partition using `len`, no need to check further
if (sum == 0) {
// [Pruning 7] Failed to make the first partition, `target` can not be the answer
if (cnt == 0) {
skip = true;
}
return;
}
}
}
}

int main() {
cin.tie(nullptr);
ios_base::sync_with_stdio(false);

int n;
cin >> n;

int len;
int largest = 0; // The largest stick's length
int sum = 0; // Sum of all sticks' lengths
vector<int> count(51); // Count of sticks per length
for (int i = 0; i < n; i++) {
cin >> len;
count[len]++;
largest = max(largest, len);
sum += len;
}

// [Pruning 1] The smallest possible answer is the length of the largest stick
// [Pruning 2] If no answer is present until `sum / 2`, the answer is `sum` (all sticks together)
for (int test = largest; test <= sum / 2; test++) {
// [Pruning 3] Only divisors of `sum` are the possible answers
if (sum % test == 0) {
skip = false;
backtracking(count, largest, n, test);
}
}
cout << sum << '\n';

return 0;
}

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