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Correct expr for expected transmissions
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pratikunterwegs committed Apr 8, 2024
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Expand Up @@ -65,7 +65,7 @@ $$
\hat\phi = \sum_x \phi(x) p(x) dx \\
$$

If we define $\hat\phi$ to be the expected number of transmissions to a given individual of type $x$, we can therefore calculate the probability that this individual remains susceptible. This gives the following relationship between $\phi$ and $\hat\phi$:
If we define $x\hat\phi$ to be the expected number of transmissions to a given individual of type $x$, we can therefore calculate the probability that this individual remains susceptible. This gives the following relationship between $\phi$ and $\hat\phi$:

$$
1-\phi(x) = S(x,0) e^{-x \hat\phi } \\
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