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Merge pull request #82 from dh-tech/feature/75-example-usage
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Add example usage to the readme #75
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rlskoeser committed Jul 11, 2024
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129 changes: 129 additions & 0 deletions README.md
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Expand Up @@ -22,6 +22,135 @@ It was initially created as part of a [DH-Tech](https://dh-tech.github.io/) hack

Read [Contributors](CONTRIBUTORS.md) for detailed contribution information.

## Example Usage

Often humanities and cultural data include imprecise or uncertain temporal information. We want to store that information but also work with it in a structured way, not just treat it as text for display. Different projects may need to work with or convert between different date formats or even different calendars.

An `undate.Undate` is analogous to python's builtin `datetime.date` object, but with support for varying degrees of precision and unknown information. You can initialize an undate with either strings or numbers for whichever parts of the date are known or partially known. An `Undate` can take an optional label.
```python
from undate.undate import Undate

november7 = Undate(2000, 11, 7)
november = Undate(2000, 11)
year2k = Undate(2000)
november7_some_year = Undate(month=11, day=7)

partially_known_year = Undate("19XX")
partially_known_month = Undate(2022, "1X")

easter1916 = Undate(1916, 4, 23, label="Easter 1916")
```

You can convert an `Undate` to string using a date formatter (current default is ISO8601):
```python
>>> [str(d) for d in [november7, november, year2k, november7_some_year]]
['2000-11-07', '2000-11', '2000', '--11-07']
```

If enough information is known, an `Undate` object can report on its duration:
```python
>>> december = Undate(2000, 12)
>>> feb_leapyear = Undate(2024, 2)
>>> feb_regularyear = Undate(2023, 2)
>>> for d in [november7, november, december, year2k, november7_some_year, feb_regularyear, feb_leapyear]:
... print(f"{d} - duration in days: {d.duration().days}")
...
2000-11-07 - duration in days: 1
2000-11 - duration in days: 30
2000-12 - duration in days: 31
2000 - duration in days: 366
--11-07 - duration in days: 1
2023-02 - duration in days: 28
2024-02 - duration in days: 29
```

If enough of the date is known and the precision supports it, you can check if one date falls within another date:
```python
>>> november7 = Undate(2000, 11, 7)
>>> november2000 = Undate(2000, 11)
>>> year2k = Undate(2000)
>>> ad100 = Undate(100)
>>> november7 in november
True
>>> november2000 in year2k
True
>>> november7 in year2k
True
>>> november2000 in ad100
False
>>> november7 in ad100
False
```

For dates that are imprecise or partially known, `undate` calculates earliest and latest possible dates for comparison purposes so you can sort dates and compare with equals, greater than, and less than. You can also compare with python `datetime.date` objects.

```python
>>> november7_2020 = Undate(2020, 11, 7)
>>> november_2001 = Undate(2001, 11)
>>> year2k = Undate(2000)
>>> ad100 = Undate(100)
>>> sorted([november7_2020, november_2001, year2k, ad100])
[<Undate 0100>, <Undate 2000>, <Undate 2001-11>, <Undate 2020-11-07>]
>>> november7_2020 > november_2001
True
>>> year2k < ad100
False
>>> from datetime import date
>>> year2k > date(2001, 1, 1)
False
```

When dates cannot be compared due to ambiguity or precision, comparison methods raise a `NotImplementedError`.

```python
>>> november_2020 = Undate(2020, 11)
>>> november7_2020 > november_2020
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "/Users/rkoeser/workarea/github/undate-python/src/undate/undate.py", line 262, in __gt__
return not (self < other or self == other)
File "/Users/rkoeser/workarea/github/undate-python/src/undate/undate.py", line 245, in __lt__
raise NotImplementedError(
NotImplementedError: Can't compare when one date falls within the other
```

An `UndateInterval` is a date range between two `Undate` objects. Intervals can be open-ended, allow for optional labels, and can calculate duration if enough information is known
```python
>>> from undate.undate import UndateInterval
>>> UndateInterval(Undate(1900), Undate(2000))
<UndateInterval 1900/2000>
>>> UndateInterval(Undate(1900), Undate(2000), label="19th century")
>>> UndateInterval(Undate(1900), Undate(2000), label="19th century").duration().days
36890
<UndateInterval '19th century' (1900/2000)>
>>> UndateInterval(Undate(1900), Undate(2000), label="20th century")
<UndateInterval '20th century' (1900/2000)>
>>> UndateInterval(latest=Undate(2000)) # before 2000
<UndateInterval ../2000>
>>> UndateInterval(Undate(1900)) # after 1900
<UndateInterval 1900/>
>>> UndateInterval(Undate(1900), Undate(2000), label="19th century").duration().days
36890
>>> UndateInterval(Undate(2000, 1, 1), Undate(2000, 1,31)).duration().days
31
```

You can initialize `Undate` or `UndateInterval` objects by parsing a date string with a specific formatter.
```python
>>> from undate.dateformat.iso8601 import ISO8601DateFormat
>>> isoformatter = ISO8601DateFormat()
>>> isoformatter.parse("2002")
<Undate 2002>
>>> isoformatter.parse("2002-05")
<Undate 2002-05>
>>> isoformatter.parse("--05-03")
<Undate --05-03>
>>> isoformatter.parse("--05-03")
<Undate --05-03>
>>> isoformatter.parse("1800/1900")
<UndateInterval 1800/1900>
```

## Documentation

Project documentation is available on ReadTheDocs https://undate-python.readthedocs.io/en/latest/
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2 changes: 1 addition & 1 deletion src/undate/undate.py
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Expand Up @@ -20,7 +20,7 @@ class DatePrecision(IntEnum):
of the date is known."""

# numbers should be set to allow logical greater than / less than
# comparison, e.g. year precision > month
# comparison, e.g. year precision < month

#: day
DAY = 1
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