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Sql edits to basic_instruct and classic sql-eval #129

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6 changes: 3 additions & 3 deletions data/instruct_basic_postgres.csv
Original file line number Diff line number Diff line change
@@ -1,6 +1,6 @@
db_name,query_category,question,query
broker,basic_join_date_group_order_limit,"What are the top 5 countries by total transaction amount in the past 30 days, inclusive of 30 days ago? Return the country name, number of transactions and total transaction amount.","SELECT c.sbCustCountry, COUNT(t.sbTxId) AS num_transactions, SUM(t.sbTxAmount) AS total_amount FROM sbCustomer c JOIN sbTransaction t ON c.sbCustId = t.sbTxCustId WHERE t.sbTxDateTime >= CURRENT_DATE - INTERVAL '30 days' GROUP BY c.sbCustCountry ORDER BY total_amount DESC LIMIT 5"
broker,basic_join_date_group_order_limit,"How many distinct customers made each type of transaction between Jan 1, 2023 and Mar 31, 2023 (inclusive of start and end dates)? Return the transaction type, number of distinct customers and average number of shares, for the top 3 transaction types by number of customers.","SELECT t.sbTxType, COUNT(DISTINCT c.sbCustId) AS num_customers, AVG(t.sbTxShares) AS avg_shares FROM sbTransaction t JOIN sbCustomer c ON t.sbTxCustId = c.sbCustId WHERE t.sbTxDateTime BETWEEN '2023-01-01' AND '2023-03-31' GROUP BY t.sbTxType ORDER BY num_customers DESC LIMIT 3"
broker,basic_join_date_group_order_limit,"How many distinct customers made each type of transaction between Jan 1, 2023 and Mar 31, 2023 (inclusive of start and end dates)? Return the transaction type, number of distinct customers and average number of shares, for the top 3 transaction types by number of customers.","SELECT t.sbTxType, COUNT(DISTINCT t.sbTxCustId) AS num_customers, AVG(t.sbTxShares) AS avg_shares FROM sbTransaction t WHERE t.sbTxDateTime BETWEEN '2023-01-01' AND '2023-03-31 23:59:59' GROUP BY t.sbTxType ORDER BY num_customers DESC LIMIT 3"
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Thanks for the fix!

broker,basic_join_group_order_limit,"What are the top 10 ticker symbols by total transaction amount? Return the ticker symbol, number of transactions and total transaction amount.","SELECT tk.sbTickerSymbol, COUNT(tx.sbTxId) AS num_transactions, SUM(tx.sbTxAmount) AS total_amount FROM sbTicker tk JOIN sbTransaction tx ON tk.sbTickerId = tx.sbTxTickerId GROUP BY tk.sbTickerSymbol ORDER BY total_amount DESC LIMIT 10"
broker,basic_join_group_order_limit,"What are the top 5 combinations of customer state and ticker type by number of transactions? Return the customer state, ticker type and number of transactions.","SELECT c.sbCustState, t.sbTickerType, COUNT(*) AS num_transactions FROM sbTransaction tx JOIN sbCustomer c ON tx.sbTxCustId = c.sbCustId JOIN sbTicker t ON tx.sbTxTickerId = t.sbTickerId GROUP BY c.sbCustState, t.sbTickerType ORDER BY num_transactions DESC LIMIT 5"
broker,basic_join_distinct,Return the distinct list of customer IDs who have made a 'buy' transaction.,SELECT DISTINCT c.sbCustId FROM sbCustomer c JOIN sbTransaction t ON c.sbCustId = t.sbTxCustId WHERE t.sbTxType = 'buy'
Expand All @@ -10,7 +10,7 @@ broker,basic_group_order_limit,What are the top 5 countries by number of custome
broker,basic_left_join,Return the customer ID and name of customers who have not made any transactions.,"SELECT c.sbCustId, c.sbCustName FROM sbCustomer c LEFT JOIN sbTransaction t ON c.sbCustId = t.sbTxCustId WHERE t.sbTxCustId IS NULL"
broker,basic_left_join,Return the ticker ID and symbol of tickers that do not have any daily price records.,"SELECT tk.sbTickerId, tk.sbTickerSymbol FROM sbTicker tk LEFT JOIN sbDailyPrice dp ON tk.sbTickerId = dp.sbDpTickerId WHERE dp.sbDpTickerId IS NULL"
car_dealership,basic_join_date_group_order_limit,"Who were the top 3 sales representatives by total revenue in the past 3 months, inclusive of today's date? Return their first name, last name, total number of sales and total revenue.","SELECT c.first_name, c.last_name, COUNT(s.id) AS total_sales, SUM(s.sale_price) AS total_revenue FROM sales s JOIN salespersons c ON s.salesperson_id = c.id WHERE s.sale_date >= CURRENT_DATE - INTERVAL '3 months' GROUP BY c.first_name, c.last_name ORDER BY total_revenue DESC LIMIT 3"
car_dealership,basic_join_date_group_order_limit,"Return the top 5 salespersons by number of sales in the past 30 days? Return their first and last name, total sales count and total revenue amount.","SELECT sp.first_name, sp.last_name, COUNT(s.id) AS total_sales, SUM(s.sale_price) AS total_revenue FROM sales s JOIN salespersons sp ON s.salesperson_id = sp.id WHERE s.sale_date >= CURRENT_DATE - INTERVAL '30 days' GROUP BY sp.first_name, sp.last_name ORDER BY total_sales DESC LIMIT 5"
car_dealership,basic_join_date_group_order_limit,"Return the top 5 salespersons by number of sales in the past 30 days? Return their first and last name, total sales count and total revenue amount.","SELECT sp.first_name, sp.last_name, COUNT(s.id) AS total_sales, SUM(s.sale_price) AS total_revenue FROM sales s JOIN salespersons sp ON s.salesperson_id = sp.id WHERE s.sale_date >= CURRENT_DATE - INTERVAL '30 days' GROUP BY sp.first_name, sp.last_name, sp.id ORDER BY total_sales DESC LIMIT 5"
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Just checking if we need the additional sp.id group by (since it's not in the select statements)?

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I think it's safer to group by id since there technically could be duplicates of first_name, last_name?

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Aight sounds good!

car_dealership,basic_join_group_order_limit,"Return the top 5 states by total revenue, showing the number of unique customers and total revenue for each state.","SELECT c.state, COUNT(DISTINCT s.customer_id) AS unique_customers, SUM(s.sale_price) AS total_revenue FROM sales s JOIN customers c ON s.customer_id = c.id GROUP BY c.state ORDER BY total_revenue DESC LIMIT 5"
car_dealership,basic_join_group_order_limit,"What are the top 5 best selling car models by total revenue? Return the make, model, total number of sales and total revenue.","SELECT c.make, c.model, COUNT(s.id) AS total_sales, SUM(s.sale_price) AS total_revenue FROM sales s JOIN cars c ON s.car_id = c.id GROUP BY c.make, c.model ORDER BY total_revenue DESC LIMIT 5"
car_dealership,basic_join_distinct,"Return the distinct list of customer IDs that have made a purchase, based on joining the customers and sales tables.",SELECT DISTINCT c.id AS customer_id FROM customers c JOIN sales s ON c.id = s.customer_id
Expand All @@ -34,7 +34,7 @@ ewallet,basic_join_date_group_order_limit,"How many distinct active users sent m
ewallet,basic_join_group_order_limit,"What are the top 3 most frequently used coupon codes? Return the coupon code, total number of redemptions, and total amount redeemed.","SELECT c.code AS coupon_code, COUNT(t.txid) AS redemption_count, SUM(t.amount) AS total_discount FROM consumer_div.coupons c JOIN consumer_div.wallet_transactions_daily t ON c.cid = t.coupon_id GROUP BY c.code ORDER BY redemption_count DESC LIMIT 3"
ewallet,basic_join_group_order_limit,"Which are the top 5 countries by total transaction amount sent by users, sender_type = 0? Return the country, number of distinct users who sent, and total transaction amount.","SELECT u.country, COUNT(DISTINCT t.sender_id) AS user_count, SUM(t.amount) AS total_amount FROM consumer_div.users u JOIN consumer_div.wallet_transactions_daily t ON u.uid = t.sender_id WHERE t.sender_type = 0 GROUP BY u.country ORDER BY total_amount DESC LIMIT 5"
ewallet,basic_join_distinct,Return the distinct list of merchant IDs that have received money from a transaction. Include all transaction types in the results you return.,SELECT DISTINCT m.mid AS merchant_id FROM consumer_div.merchants m JOIN consumer_div.wallet_transactions_daily t ON m.mid = t.receiver_id WHERE t.receiver_type = 1
ewallet,basic_join_distinct,Return the distinct list of user IDs who have received transaction notifications.,SELECT DISTINCT u.uid AS user_id FROM consumer_div.users u JOIN consumer_div.notifications n ON u.uid = n.user_id WHERE n.type = 'transaction'
ewallet,basic_join_distinct,Return the distinct list of user IDs who have received transaction notifications.,SELECT DISTINCT user_id FROM consumer_div.notifications WHERE type = 'transaction'
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Oh yay thanks for simplifying this!

ewallet,basic_group_order_limit,What are the top 3 most common transaction statuses and their respective counts?,"SELECT status, COUNT(*) AS COUNT FROM consumer_div.wallet_transactions_daily GROUP BY status ORDER BY COUNT DESC LIMIT 3"
ewallet,basic_group_order_limit,What are the top 2 most frequently used device types for user sessions and their respective counts?,"SELECT device_type, COUNT(*) AS COUNT FROM consumer_div.user_sessions GROUP BY device_type ORDER BY COUNT DESC LIMIT 2"
ewallet,basic_left_join,Return users (user ID and username) who have not received any notifications,"SELECT u.uid, u.username FROM consumer_div.users u LEFT JOIN consumer_div.notifications n ON u.uid = n.user_id WHERE n.id IS NULL"
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