clarified phrasing for a question

data/questions_gen_postgres.csv

@@ -232,6 +232,6 @@ Assume the rating of a business to be its average rating, and compute it before
 "Which merchants earliest coupon start date was within a year of the merchant's registration? Return the merchant id, registration date, and earliest coupon id and start date","WITH earliest_coupons AS (SELECT c.merchant_id, MIN(c.start_date) AS earliest_coupon_start_date FROM consumer_div.coupons c GROUP BY c.merchant_id) SELECT m.mid AS merchant_id, m.created_at AS merchant_registration_date, ec.earliest_coupon_start_date, c.cid AS earliest_coupon_id FROM consumer_div.merchants m JOIN earliest_coupons ec ON m.mid = ec.merchant_id JOIN consumer_div.coupons c ON ec.merchant_id = c.merchant_id AND ec.earliest_coupon_start_date = c.start_date WHERE ec.earliest_coupon_start_date <= m.created_at + INTERVAL '1 year';",ewallet,date_functions,
 "Return the name and phone number of the salesperson with the shortest time from being hired to getting fired. Return the number of days he/she was employed for.","SELECT s.first_name, s.last_name, s.phone, s.termination_date - s.hire_date AS days_employed FROM salespersons s ORDER BY days_employed ASC LIMIT 1;",car_dealership,date_functions,
 "Return the number of payments made on weekends to the vendor named 'Utility Company'","SELECT COUNT(*) AS weekend_payments FROM payments_made WHERE vendor_name = 'Utility Company' AND EXTRACT(DOW FROM payment_date) IN (0, 6);",car_dealership,date_functions,
-"show me the daily total amount of payments received in the whole of last week, split by the payment_method","SELECT payment_date, payment_method, SUM(payment_amount) AS total_amount FROM payments_received WHERE payment_date BETWEEN DATE_TRUNC('WEEK', CURRENT_DATE) - INTERVAL '1 week' AND DATE_TRUNC('WEEK', CURRENT_DATE) GROUP BY payment_date, payment_method ORDER BY payment_date DESC, payment_method ASC;",car_dealership,date_functions,
+"show me the daily total amount of payments received in the whole of the last ISO week, split by the payment_method","SELECT payment_date, payment_method, SUM(payment_amount) AS total_amount FROM payments_received WHERE payment_date >= DATE_TRUNC('WEEK', CURRENT_DATE) - INTERVAL '1 week' AND payment_date < DATE_TRUNC('WEEK', CURRENT_DATE) GROUP BY payment_date, payment_method ORDER BY payment_date DESC, payment_method ASC;",car_dealership,date_functions,
 "Which cars were in inventory in the latest snapshot for march 2023? Return the car id, make, model, and year.","WITH latest_snapshot AS (SELECT MAX(snapshot_date) AS snapshot_date FROM inventory_snapshots WHERE snapshot_date BETWEEN '2023-03-01' AND '2023-03-31' ), latest_snapshot_data AS (SELECT inv.car_id FROM inventory_snapshots inv JOIN latest_snapshot ls ON inv.snapshot_date = ls.snapshot_date WHERE inv.is_in_inventory = TRUE ) SELECT c.id, c.make, c.model, c.year FROM cars c JOIN latest_snapshot_data lsd ON c.id = lsd.car_id;",car_dealership,date_functions,
 "What were the total quarterly sales in 2023 grouped by customer's state? Represent each quarter as the first date in the quarter.","SELECT DATE_TRUNC('QUARTER', s.sale_date) AS QUARTER, c.state, SUM(s.sale_price) AS total_sales FROM sales s JOIN customers c ON s.customer_id = c.id WHERE EXTRACT(YEAR FROM s.sale_date) = 2023 GROUP BY c.state, QUARTER HAVING SUM(s.sale_price) > 0 ORDER BY QUARTER, c.state ;",car_dealership,date_functions,