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Solve Bananagrams with any lexicon and set of tiles

Usage:

from graph import DirectedGraph, trie_to_dawg
from bananagram import Bananagrams

lexicon = open('data/sowpods.txt', 'r').read()
G = DirectedGraph()
G.parselex(lexicon)  # build prefix trie
trie_to_dawg(G)  # reduce graph by merging suffixes

B = Bananagrams(G)

#  Available tiles
rack = [s for s in 'lbwnytkmexroatiliaape']
sol = B.solve(rack)

B.show(sol)  # Print solution!
""" Outputs:
3210123
2  P
1 MIB
0TI AA
1 R LAWN
2 Y L
3   O
4   T
5   E
6  KEX
"""

Bananagrams:

The rules are simple:

Randomly collect N letter tiles Use all N letters to make a Scrabble-like grid of words. If no solution exists, grab more tiles

The Question: for N randomly grabbed letters, how likely is it that a solution exist?

Sub-questions:

  1. As N increases, how does likelihood of solution change? Where does the change occur?
  2. How does the behavior depend on the distribution of letters grabbable?

Sources:

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