Skip to content

Commit

Permalink
Finsihing Chapter 9, adding ToC and title page.
Browse files Browse the repository at this point in the history
  • Loading branch information
b-butler committed Jun 5, 2019
1 parent c3bd843 commit 21a192d
Show file tree
Hide file tree
Showing 4 changed files with 32 additions and 5 deletions.
2 changes: 1 addition & 1 deletion chapters/ch3.tex
Original file line number Diff line number Diff line change
Expand Up @@ -105,7 +105,7 @@ \section{Gibb's Ensemble}\label{sec:Gibb's Ensemble}
True to its name the natural thermodynamic function for the Gibb's ensemble is
Gibb's energy.

\section{MicroCanonical Ensembles}%
\section{MicroCanonical Ensemble}%
\label{sec:MicroCanonical}

\subsection{Universality of Microcanonical Ensemble}
Expand Down
28 changes: 27 additions & 1 deletion chapters/ch9.tex
Original file line number Diff line number Diff line change
Expand Up @@ -184,4 +184,30 @@ \subsection{Zero of Energy}
e^{D_o /kT}.
\end{align*}
The substitution to $D_o$ is graphically explained in
Figure~\ref{fig:diatomicelectronic}.
Figure~\ref{fig:diatomicelectronic}. From the graphical argument and the
definition of $D_o$, $-D_{o}$ can been seen to be the total ground state energy
from our original convention. Thus, for any zero energy convention the partition
function is
\begin{equation*}
q = q^0 e^{-\varepsilon_{0}^0 /kT}.
\end{equation*}
Substituting this into the equation for chemical potential we have,
\begin{align*}
\mu &= -kT\ln{\left[\frac{q}{V} kT \right]} + kT\ln{[p]} \\
&= -kT\ln{\left[e^{-\varepsilon^0_0}\frac{q^0}{V} kT \right]} +
kT\ln{[p]} \\
\mu - \varepsilon^0_0 &= -kT\ln{\left[\frac{q^0}{V} kT \right]} +
kT\ln{[p]}.
\end{align*}
An important fact here is that $\mu \to \varepsilon$ as $T \to 0$. If we treat
$\mu - \varepsilon^0_0$ as the relative chemical potential, then it goes to 0 at
$T \to 0$. Multiplying by Avogadro's number, we obtain,
\begin{equation*}
G^0 - E^0_0 = -RT \ln{\left[\frac{q^0}{V} kT \right]} + kT\ln{[p]}.
\end{equation*}
This means that $E^0$ is the standard free energy at 0 K which means $G^0 -
G^0_0$ is an equally appropriate choice. Likewise, since $H = E + pV$ and $p \to
0$ as $T \to 0$, then $H^0_0 = E^0_0 $. Thus, these three notations are
equivalent and possible. An important comment on convention is required to use
the derived quantities above. An elements energy is considered 0 at 0 K if the
element is in the same physical state that is stable at $25^{\circ}$C and 1 atm.
Binary file modified notes.pdf
Binary file not shown.
7 changes: 4 additions & 3 deletions notes.tex
Original file line number Diff line number Diff line change
Expand Up @@ -8,9 +8,9 @@
\usepackage{graphicx}
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%

\title{McQuarrie Stat Mech Notes}
\title{Stat Mech Notes}
\author{Brandon Butler}
\date{2019--04--02}
\date{2019--06--05}
\graphicspath{{./media/}}

% User defined commands
Expand All @@ -21,7 +21,8 @@
\newcommand{\chapterpath}[1]{./chapters/#1}
\newcommand{\nint}[1]{\int\cdots\int{#1}}
\begin{document}

\maketitle
\tableofcontents\newpage
\chapter{Canonical Ensemble}
\include{\chapterpath{ch2}}
\chapter{Other Ensembles and Fluctuations}
Expand Down

0 comments on commit 21a192d

Please sign in to comment.