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Solution to problem 1 #1791

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19 changes: 19 additions & 0 deletions Project Euler Solutions/Problem 1.py
Original file line number Diff line number Diff line change
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'''
If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. The sum of these multiples is 23.
Find the sum of all the multiples of 3 or 5 below 1000.
'''

n = 1000
numbers = []
soln = 0

for i in range(n):
if i%3 == 0:
if i%5 != 0:
soln += i
elif i%5 == 0:
if i%3 != 0:
soln += i


print(f"the sum of all the multiples of 3 or 5 below 1000 is {soln}")