update slides 23 and 24 to include ARRAY-based SQL equivalents

TutDForSQLDevelopers/23.slidedata

@@ -46,8 +46,16 @@ TutorialD (master/main): :showexpr (p : {suppliers := (sp rename {p# as pid} whe
 │        │└────────┘                    │
 └────────┴──────────────────────────────┘
 
-Not supported.
-
+SELECT p."p#", ARRAY(SELECT sp."s#" FROM sp WHERE sp."p#" = p."p#") FROM p;
 
+ p# |     array     
+----+---------------
+ P6 | {S1}
+ P3 | {S1}
+ P4 | {S1,S4}
+ P1 | {S2,S1}
+ P2 | {S2,S4,S3,S1}
+ P5 | {S4,S1}
+ P7 | {}
 
 Show each product mapped to its suppliers. Note that "P7" does not have any suppliers; this is represented by an empty relation in the "suppliers" column.

TutDForSQLDevelopers/24.slidedata

@@ -19,8 +19,21 @@ TutorialD (master/main): :showexpr ((p : {suppliers := (sp rename {p# as pid} wh
 │"P5"    │"S1"    │
 └────────┴────────┘
 
-Not supported.
-
+WITH p_grouped AS (SELECT p."p#", ARRAY(SELECT sp."s#" FROM sp WHERE sp."p#" = p."p#") AS ss FROM p) SELECT "p#",UNNEST(ss) AS "s#" FROM p_grouped;
 
+ p# | s# 
+----+----
+ P6 | S1
+ P3 | S1
+ P4 | S1
+ P4 | S4
+ P1 | S2
+ P1 | S1
+ P2 | S2
+ P2 | S4
+ P2 | S3
+ P2 | S1
+ P5 | S4
+ P5 | S1
 
 Map all products to their constituent suppliers (group), then flatten (ungroup) the mapping. Note that product "P7" is missing.