[hyogshin] WEEK 01 solutions #1723
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sora0319
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Jul 26, 2025
| - set(nums) -> O(n) | ||
| - sorted(list(s)) -> O(n log n) | ||
| - for loop -> O(n) | ||
| - O(2n) + O(n log n) => O(2n) 이 아니라 왜 O(n log n) 이지? |
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2N은 즉, N의 그래프의 배수이기 때문에 NlogN의 그래프와 비교해서 항상 작은 값을 가지게 됩니다
그래서 항상 더 큰 값을 가지는 NlogN으로 시간복잡도가 정해집니다
표기를 빅오 표기법이라, 최악의 상황으로 시간복잡도를 정해서 NlogN이 됩니다
| ''' | ||
| 시간 복잡도: O(1) | ||
| - for loop -> 보통 O(n) 이지만, 길이 10001 짜리 고정 배열 -> O(1)로 취급 가능 | ||
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고정 배열이라도 결국 nums를 처음 for문에서 반복하고 있으므로 O(N)이라고 생각이 드는데 어떻게 생각하시나요?
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