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[moonhyeok] Week10 #1015
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[moonhyeok] Week10 #1015
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Original file line number | Diff line number | Diff line change |
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/** | ||
* Source: https://leetcode.com/problems/invert-binary-tree/ | ||
* 풀이방법: 재귀를 이용하여 트리를 뒤집음 | ||
* | ||
* 시간복잡도: O(n) - n은 트리의 노드 수 | ||
* 공간복잡도: O(n) - 재귀 호출에 따른 스택 메모리 | ||
* | ||
* 다른 풀이방법 | ||
* - BFS를 이용하여 풀이 | ||
* - 스택을 이용하여 풀이 | ||
*/ | ||
|
||
/** | ||
* Definition for a binary tree node. | ||
* class TreeNode { | ||
* val: number | ||
* left: TreeNode | null | ||
* right: TreeNode | null | ||
* constructor(val?: number, left?: TreeNode | null, right?: TreeNode | null) { | ||
* this.val = (val===undefined ? 0 : val) | ||
* this.left = (left===undefined ? null : left) | ||
* this.right = (right===undefined ? null : right) | ||
* } | ||
* } | ||
*/ | ||
|
||
function invertTree(root: TreeNode | null): TreeNode | null { | ||
if (!root) return null; | ||
|
||
const result = new TreeNode( | ||
root.val, | ||
invertTree(root.right), | ||
invertTree(root.left) | ||
); | ||
return result; | ||
} |
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재귀를 통해 풀어주셨군요! 👍 코드에서는 TreeNode를 새로 만들어서 return하는데 in-place로 구현할 수도 있을것같아요
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감사합니다. in-place로 바로 결과를 보낼 수 있는걸 잊었네요 ㅎㅎ