Scissors - Aida R. #50
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CheezItMan
reviewed
Jan 11, 2022
| elif current_node.key < key: | ||
| current_node.right = self.add_helper(current_node.right, key, value) | ||
| return current_node | ||
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| def add(self, key, value = None): |
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| # Time Complexity: O(log n) if Balanced BST and O(n) for Unbalanced BST | ||
| # Space Complexity: O(log n) if Balanced BST and O(1) for Unbalanced BST | ||
| def find_helper(self, current, key): |
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| # Time Complexity: O(n) where n is each visited node | ||
| # Space Complexity: O(n) - O(h) for the call stack, where h is the height of the tree | ||
| # Inorder Traversal: Left - Root - Right | ||
| def inorder_helper(self, current, ascending_nodes): |
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👍 Since you're making a list of all the nodes the space complexity is O(n)
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| # Time Complexity: O(n) where n is each visited node | ||
| # Space Complexity: O(n) - O(h) for the call stack, where h is the height of the tree | ||
| # Preoder traversal: Root - Left - Right | ||
| def preorder_helper(self, current, preorder_nodes): |
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👍 Since you're making a list of all the nodes the space complexity is O(n)
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| # Time Complexity: O(n) where n is each visited node | ||
| # Space Complexity: O(n) - O(h) for the call stack, where h is the height of the tree | ||
| # Postorder traversal: Left - Right - Root | ||
| def postorder_helper(self, current, postorder_nodes): |
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👍 Since you're making a list of all the nodes the space complexity is O(n)
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| # Time Complexity: O(log n) if Balanced BST and O(n) for Unbalanced BST | ||
| # Space Complexity: O(n) where n is the number of nodes in a given binary tree. | ||
| def height_helper(self, current, current_height): |
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👍 The space complexity is correct if the tree could be unbalanced. If the tree is balanced it's O( log n )
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| # # Time Complexity: O(n) where n is the number of nodes -1 except root | ||
| # # Space Complexity: O(?) | ||
| def bfs(self): |
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