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166 changes: 134 additions & 32 deletions linked_list/linked_list.py
Original file line number Diff line number Diff line change
Expand Up @@ -9,72 +9,162 @@ def __init__(self, value, next_node = None):
# Defines the singly linked list
class LinkedList:
def __init__(self):
self.head = None # keep the head private. Not accessible outside this class
self.head = None # keep the head private. Not accessible outside this class

# returns the value in the first node
# returns None if the list is empty
# Time Complexity: ?
# Space Complexity: ?
# Time Complexity: 0(1)
# Space Complexity: 0(1)
def get_first(self):
Comment on lines +16 to 18

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👍

pass

if self.head == None:
return None

return self.head.value

# method to add a new node with the specific data value in the linked list
# insert the new node at the beginning of the linked list
# Time Complexity: ?
# Space Complexity: ?
# Time Complexity: 0(1)
# Space Complexity: 0(n)
def add_first(self, value):
Comment on lines +27 to 29

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👍 However the space complexity is O(1) because you're only ever adding 1 node.

pass
node = Node(value, next_node=self.head)
self.head = node

# method to find if the linked list contains a node with specified value
# returns true if found, false otherwise
# Time Complexity: ?
# Space Complexity: ?
# Time Complexity: 0(n)
# Space Complexity: 0(1)
def search(self, value):
Comment on lines +35 to 37

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👍

pass
current = self.head

while current:
if current.value == value:
return True
current = current.next

return False


# method that returns the length of the singly linked list
# Time Complexity: ?
# Space Complexity: ?
# Time Complexity: 0(n)
# Space Complexity: 0(1)
def length(self):
Comment on lines +49 to 51

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👍

pass

count = 0

current = self.head

while current:

current = current.next
count += 1

return count

# method that returns the value at a given index in the linked list
# index count starts at 0
# returns None if there are fewer nodes in the linked list than the index value
# Time Complexity: ?
# Space Complexity: ?
# Time Complexity: 0(n)
# Space Complexity: 0(1)
def get_at_index(self, index):
Comment on lines +67 to 69

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👍

pass

if self.head == None:
return None

if index == 0:
return self.head.value

current = self.head
counter = 0

# index - 1 --> we are manipulating the pointer for the previous node
while current.next and counter < index - 1:
current = current.next
counter += 1

if current.next:
return current.next.value


# method that returns the value of the last node in the linked list
# returns None if the linked list is empty
# Time Complexity: ?
# Space Complexity: ?
# Time Complexity: 0(n)
# Space Complexity: 0(1)
def get_last(self):
Comment on lines +91 to 93

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👍

pass

if self.head == None:
return None

current = self.head
while current.next:
current = current.next

return current.value


# method that inserts a given value as a new last node in the linked list
# Time Complexity: ?
# Space Complexity: ?
# Time Complexity: 0(n)
# Space Complexity: 0(1)
def add_last(self, value):
pass

if self.head == None:
self.head = Node(value, None)
return

current = self.head

while current.next:
current = current.next

current.next = Node(value, None)


# method to return the max value in the linked list
# returns the data value and not the node
def find_max(self):
pass

if self.head == None:
return None

current = self.head
max = 0

while current:
if current.value > max:
max = current.value
current = current.next

return max

# method to delete the first node found with specified value
# Time Complexity: ?
# Space Complexity: ?
# Time Complexity: 0(n)
# Space Complexity: 0(1)
def delete(self, value):
Comment on lines +140 to 142

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👍

pass

if self.head == None:
return None


if self.head.value == value:
self.head = self.head.next
return

current = self.head

while current:
if current.value == value:
break
previous = current
current = current.next

previous.next = current.next


# method to print all the values in the linked list
# Time Complexity: ?
# Space Complexity: ?
# Time Complexity: 0(n)
# Space Complexity: 0(1)
def visit(self):
Comment on lines +164 to 166

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👍


helper_list = []
current = self.head

Expand All @@ -83,14 +173,25 @@ def visit(self):
current = current.next

print(", ".join(helper_list))


# method to reverse the singly linked list
# note: the nodes should be moved and not just the values in the nodes
# Time Complexity: ?
# Space Complexity: ?
# Time Complexity: 0(1)
# Space Complexity: 0(n)
def reverse(self):
Comment on lines +180 to 182

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👍 However the time complexity is O(n) and space complexity is O(1)

pass


previous = None
current = self.head

while current:
next = current.next
current.next = previous
previous = current
current = next

self.head = previous

## Advanced/ Exercises
# returns the value at the middle element in the singly linked list
# Time Complexity: ?
Expand Down Expand Up @@ -126,3 +227,4 @@ def create_cycle(self):
current = current.next

current.next = self.head # make the last node link to first node