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M. Nguyen - Linked List #45
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@@ -9,72 +9,162 @@ def __init__(self, value, next_node = None): | |
# Defines the singly linked list | ||
class LinkedList: | ||
def __init__(self): | ||
self.head = None # keep the head private. Not accessible outside this class | ||
self.head = None # keep the head private. Not accessible outside this class | ||
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# returns the value in the first node | ||
# returns None if the list is empty | ||
# Time Complexity: ? | ||
# Space Complexity: ? | ||
# Time Complexity: 0(1) | ||
# Space Complexity: 0(1) | ||
def get_first(self): | ||
pass | ||
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if self.head == None: | ||
return None | ||
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return self.head.value | ||
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# method to add a new node with the specific data value in the linked list | ||
# insert the new node at the beginning of the linked list | ||
# Time Complexity: ? | ||
# Space Complexity: ? | ||
# Time Complexity: 0(1) | ||
# Space Complexity: 0(n) | ||
def add_first(self, value): | ||
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There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. 👍 However the space complexity is O(1) because you're only ever adding 1 node. |
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pass | ||
node = Node(value, next_node=self.head) | ||
self.head = node | ||
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# method to find if the linked list contains a node with specified value | ||
# returns true if found, false otherwise | ||
# Time Complexity: ? | ||
# Space Complexity: ? | ||
# Time Complexity: 0(n) | ||
# Space Complexity: 0(1) | ||
def search(self, value): | ||
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There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. 👍 |
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pass | ||
current = self.head | ||
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while current: | ||
if current.value == value: | ||
return True | ||
current = current.next | ||
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return False | ||
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# method that returns the length of the singly linked list | ||
# Time Complexity: ? | ||
# Space Complexity: ? | ||
# Time Complexity: 0(n) | ||
# Space Complexity: 0(1) | ||
def length(self): | ||
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There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. 👍 |
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pass | ||
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count = 0 | ||
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current = self.head | ||
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while current: | ||
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current = current.next | ||
count += 1 | ||
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return count | ||
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# method that returns the value at a given index in the linked list | ||
# index count starts at 0 | ||
# returns None if there are fewer nodes in the linked list than the index value | ||
# Time Complexity: ? | ||
# Space Complexity: ? | ||
# Time Complexity: 0(n) | ||
# Space Complexity: 0(1) | ||
def get_at_index(self, index): | ||
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There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. 👍 |
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pass | ||
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if self.head == None: | ||
return None | ||
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if index == 0: | ||
return self.head.value | ||
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current = self.head | ||
counter = 0 | ||
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# index - 1 --> we are manipulating the pointer for the previous node | ||
while current.next and counter < index - 1: | ||
current = current.next | ||
counter += 1 | ||
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if current.next: | ||
return current.next.value | ||
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# method that returns the value of the last node in the linked list | ||
# returns None if the linked list is empty | ||
# Time Complexity: ? | ||
# Space Complexity: ? | ||
# Time Complexity: 0(n) | ||
# Space Complexity: 0(1) | ||
def get_last(self): | ||
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There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. 👍 |
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pass | ||
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if self.head == None: | ||
return None | ||
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current = self.head | ||
while current.next: | ||
current = current.next | ||
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return current.value | ||
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# method that inserts a given value as a new last node in the linked list | ||
# Time Complexity: ? | ||
# Space Complexity: ? | ||
# Time Complexity: 0(n) | ||
# Space Complexity: 0(1) | ||
def add_last(self, value): | ||
pass | ||
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if self.head == None: | ||
self.head = Node(value, None) | ||
return | ||
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current = self.head | ||
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while current.next: | ||
current = current.next | ||
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current.next = Node(value, None) | ||
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# method to return the max value in the linked list | ||
# returns the data value and not the node | ||
def find_max(self): | ||
pass | ||
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if self.head == None: | ||
return None | ||
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current = self.head | ||
max = 0 | ||
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while current: | ||
if current.value > max: | ||
max = current.value | ||
current = current.next | ||
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return max | ||
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# method to delete the first node found with specified value | ||
# Time Complexity: ? | ||
# Space Complexity: ? | ||
# Time Complexity: 0(n) | ||
# Space Complexity: 0(1) | ||
def delete(self, value): | ||
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pass | ||
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if self.head == None: | ||
return None | ||
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if self.head.value == value: | ||
self.head = self.head.next | ||
return | ||
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current = self.head | ||
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while current: | ||
if current.value == value: | ||
break | ||
previous = current | ||
current = current.next | ||
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previous.next = current.next | ||
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# method to print all the values in the linked list | ||
# Time Complexity: ? | ||
# Space Complexity: ? | ||
# Time Complexity: 0(n) | ||
# Space Complexity: 0(1) | ||
def visit(self): | ||
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helper_list = [] | ||
current = self.head | ||
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@@ -83,14 +173,25 @@ def visit(self): | |
current = current.next | ||
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print(", ".join(helper_list)) | ||
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# method to reverse the singly linked list | ||
# note: the nodes should be moved and not just the values in the nodes | ||
# Time Complexity: ? | ||
# Space Complexity: ? | ||
# Time Complexity: 0(1) | ||
# Space Complexity: 0(n) | ||
def reverse(self): | ||
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There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. 👍 However the time complexity is O(n) and space complexity is O(1) |
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pass | ||
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previous = None | ||
current = self.head | ||
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while current: | ||
next = current.next | ||
current.next = previous | ||
previous = current | ||
current = next | ||
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self.head = previous | ||
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## Advanced/ Exercises | ||
# returns the value at the middle element in the singly linked list | ||
# Time Complexity: ? | ||
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@@ -126,3 +227,4 @@ def create_cycle(self): | |
current = current.next | ||
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current.next = self.head # make the last node link to first node | ||
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👍