Paper- Glenda C #5
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CheezItMan
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Dec 4, 2021
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| def dfs(v, c): | ||
| visited[v] = True | ||
| color[v] = c | ||
| for u in dislikes[v]: | ||
| if not visited[u]: | ||
| dfs(u, 1 - c) |
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| Time Complexity: O(n^2) | ||
| Space Complexity: O(n) |
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👍 But I think the time complexity is O(NE) where N is the number of nodes and E the number of edges. I suppose in a fully connected graph it would approach O(n^2)
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