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Rock-Leilani #4

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leilanianiel
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Nice work Leilani, this works and you have a nice recursive dfs function. It has room for improvement, but does work.

Comment on lines 12 to +17
def possible_bipartition(dislikes):
""" Will return True or False if the given graph
can be bipartitioned without neighboring nodes put
into the same partition.
Time Complexity: ?
Space Complexity: ?
Time Complexity: O(n^2)
Space Complexity: O(n)

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This works, but the time complexity would be O(NE) because of the loops in lines 33-36.

This can be done using DFS in O(N + E) time, but you would need to modify your dfs helper function and how you handle the if statement in lines 30-31.

Otherwise nice dfs solution.

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