Dani Sanchez - Paper #2
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CheezItMan
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Dec 4, 2021
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| def possible_bipartition(dislikes): | ||
| """ Will return True or False if the given graph | ||
| can be bipartitioned without neighboring nodes put | ||
| into the same partition. | ||
| Time Complexity: ? | ||
| Space Complexity: ? | ||
| Time Complexity: O(n log n) | ||
| Space Complexity: O(n) | ||
| """ |
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👍 Although I think the time complexity is O(NE) where n is the number of nodes (dogs) and E is the number of edges (dislikes between dogs).
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