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Ports - Sopheary #33

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229 changes: 181 additions & 48 deletions lib/linked_list.rb
Original file line number Diff line number Diff line change
Expand Up @@ -18,132 +18,265 @@ def initialize

# method to add a new node with the specific data value in the linked list
# insert the new node at the beginning of the linked list
# Time Complexity:
# Space Complexity
# Time Complexity: O(1)
# Space Complexity O(1)
def add_first(value)
raise NotImplementedError
new_node = Node.new(value)
new_node.next = @head
@head = new_node
end

# method to find if the linked list contains a node with specified value
# returns true if found, false otherwise
# Time Complexity:
# Space Complexity
# Time Complexity: O(n)
# Space Complexity: O(1)
def search(value)
raise NotImplementedError
return false if @head.nil?
return true if @head.data = value

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Is this needed? Wouldn't the loop catch this as well?

current = @head
until current.data.nil?
return true if current.data = value
current = current.next
end
end

# method to return the max value in the linked list
# returns the data value and not the node
# Time Complexity:
# Space Complexity
# Time Complexity: O(n)
# Space Complexity: O(1)
def find_max
raise NotImplementedError
return nil if @head.nil?
current = @head
max = current.data
until current.nil?
max = current.data if current.data > max
current = current.next
end
return max
end

# method to return the min value in the linked list
# returns the data value and not the node
# Time Complexity:
# Space Complexity
# Time Complexity: O(n)
# Space Complexity: O(1)
def find_min
raise NotImplementedError
return nil if @head.nil?
current = @head
min = current.data
until current.nil?
if current.data < min
min = current.data
end
current = current.next
end
return min
end


# method that returns the length of the singly linked list
# Time Complexity:
# Space Complexity
# Time Complexity: O(n)
# Space Complexity: O(1)
def length
raise NotImplementedError
return 0 if @head.nil?
length = 0
current = @head
until current.nil?
current = current.next
length += 1
end
return length

end

# method that returns the value at a given index in the linked list
# index count starts at 0
# returns nil if there are fewer nodes in the linked list than the index value
# Time Complexity:
# Space Complexity
# Time Complexity: O(n)
# Space Complexity: O(1)
def get_at_index(index)
raise NotImplementedError
return nil if length <= index
current = @head
count = 0
until current.nil?
return current.data if count == index
current = current.next
count += 1
end
end

# method to print all the values in the linked list
# Time Complexity:
# Space Complexity
# Time Complexity: O(n)
# Space Complexity: O(1)
def visit
raise NotImplementedError
current = @head
until current.nil?
puts current.data
current = current.next
end
end

# method to delete the first node found with specified value
# Time Complexity:
# Space Complexity
# Time Complexity: O(n) where n is the number of nodes
# Space Complexity: O(1)
def delete(value)
raise NotImplementedError
return if @head.nil?
current = @head

if current.data == value
@head = current.next
return
end

prev = current
until current.nil?
if current.data == value
prev.next = current.next
else
prev = current
end
current = current.next
end
end

# method to reverse the singly linked list
# note: the nodes should be moved and not just the values in the nodes
# Time Complexity:
# Space Complexity
# Time Complexity: O(n) where n is the number of nodes
# Space Complexity: O(1)
def reverse
raise NotImplementedError
return nil if @head.nil?
prev = nil
current = @head
until current.nil?
temp = current.next
current.next = prev
prev = current
current = temp
end

@head = prev

end


## Advanced Exercises
# returns the value at the middle element in the singly linked list
# Time Complexity:
# Space Complexity
# Time Complexity: O(n)
# Space Complexity: O(1)
def find_middle_value
raise NotImplementedError
return nil if @head.nil?
current = @head
if length % 2 == 0
return nil
else
middle_index = length / 2
end
index = 0
until current.nil?
return current.data if index == middle_index
current = current.next
index += 1
end

end

# find the nth node from the end and return its value
# assume indexing starts at 0 while counting to n
# Time Complexity:
# Space Complexity
# Time Complexity: O(n)
# Space Complexity: O(1)
def find_nth_from_end(n)
raise NotImplementedError
return nil if @head.nil?
current = @head
index = 0
until current.nil?

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What if n is larger than the length of the list?

if index == length - n - 1
return current.data
end
index += 1
current = current.next
end
end

# checks if the linked list has a cycle. A cycle exists if any node in the
# linked list links to a node already visited.
# returns true if a cycle is found, false otherwise.
# Time Complexity:
# Space Complexity
# Time Complexity: O(n)
# Space Complexity: O(1)
def has_cycle
raise NotImplementedError
return nil if @head.nil?

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👍

slow_p = @head
fast_p = @head
while slow_p != nil && fast_p != nil and fast_p.next != nil
slow_p = slow_p.next
fast_p = fast_p.next.next
if slow_p == fast_p
return true
end
return false
end
end


# Additional Exercises
# returns the value in the first node
# returns nil if the list is empty
# Time Complexity:
# Space Complexity
# Time Complexity: O(1)
# Space Complexity: O(1)
def get_first
raise NotImplementedError
return nil if @head.nil?
return @head.data
end

# method that inserts a given value as a new last node in the linked list
# Time Complexity:
# Space Complexity
# Time Complexity: O(n) where n is the number of nodes
# Space Complexity: O(1)
def add_last(value)
raise NotImplementedError
new_node = Node.new(value)
if @head.nil?
@head = new_node
return
end
current = @head
until current.next.nil?
current = current.next
end
current.next = new_node

end

# method that returns the value of the last node in the linked list
# returns nil if the linked list is empty
# Time Complexity:
# Space Complexity
# Time Complexity: O(n) where n is the number of nodes
# Space Complexity: O(1)
def get_last
raise NotImplementedError
return nil if @head.nil?
current = @head
until current.next.nil?
current = current.next
end
return current.data
end

# method to insert a new node with specific data value, assuming the linked
# list is sorted in ascending order
# Time Complexity:
# Space Complexity
# Time Complexity: O(n)
# Space Complexity: O(1)
def insert_ascending(value)
raise NotImplementedError
new_node = Node.new(value)
@head = new_node if @head.nil?
current = @head
if current.data > new_node.data
temp = @head
@head = new_node
new_node.next = temp
end
until current.nil?
if current.data <= value && current.next.data > value
temp = current.next
current.next = new_node
new_node.next = temp
end
current = current.next
end
end

# Helper method for tests
Expand Down