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longest-word-in-dictionary.py
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longest-word-in-dictionary.py
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# Time: O(n), n is the total sum of the lengths of words
# Space: O(t), t is the number of nodes in trie
# Given a list of strings words representing an English Dictionary,
# find the longest word in words that can be built one character at a time by other words in words.
# If there is more than one possible answer, return the longest word with the smallest lexicographical order.
#
# If there is no answer, return the empty string.
# Example 1:
# Input:
# words = ["w","wo","wor","worl", "world"]
# Output: "world"
# Explanation:
# The word "world" can be built one character at a time by "w", "wo", "wor", and "worl".
#
# Example 2:
# Input:
# words = ["a", "banana", "app", "appl", "ap", "apply", "apple"]
# Output: "apple"
# Explanation:
# Both "apply" and "apple" can be built from other words in the dictionary.
# However, "apple" is lexicographically smaller than "apply".
#
# Note:
# - All the strings in the input will only contain lowercase letters.
# - The length of words will be in the range [1, 1000].
# - The length of words[i] will be in the range [1, 30].
# V0
# V1
# https://blog.csdn.net/fuxuemingzhu/article/details/79123277
# IDEA : GREEDY
class Solution(object):
def longestWord(self, words):
"""
:type words: List[str]
:rtype: str
"""
wset = set(words)
res = ""
for w in words:
isIn = True
for i in range(1, len(w)):
if w[:i] not in wset:
isIn = False
break
if isIn:
if not res or len(w) > len(res):
res = w
elif len(w) == len(res) and res > w:
res = w
return res
# V1'
# https://blog.csdn.net/fuxuemingzhu/article/details/79123277
# IDEA : SORT
class Solution(object):
def longestWord(self, words):
"""
:type words: List[str]
:rtype: str
"""
words.sort()
res = set([''])
longestWord = ''
for word in words:
if word[:-1] in res:
res.add(word)
if len(word) > len(longestWord):
longestWord = word
return longestWord
# V2
import collections
from functools import reduce
class Solution(object):
def longestWord(self, words):
"""
:type words: List[str]
:rtype: str
"""
_trie = lambda: collections.defaultdict(_trie)
trie = _trie()
for i, word in enumerate(words):
reduce(dict.__getitem__, word, trie)["_end"] = i
# DFS
stack = list(trie.values())
result = ""
while stack:
curr = stack.pop()
if "_end" in curr:
word = words[curr["_end"]]
if len(word) > len(result) or (len(word) == len(result) and word < result):
result = word
stack += [curr[letter] for letter in curr if letter != "_end"]
return result