LeetCode_225.py

"""
请你仅使用两个队列实现一个后入先出（LIFO）的栈，并支持普通栈的全部四种操作（push、top、pop 和 empty）。

实现 MyStack 类：

void push(int x) 将元素 x 压入栈顶。
int pop() 移除并返回栈顶元素。
int top() 返回栈顶元素。
boolean empty() 如果栈是空的，返回 true ；否则，返回 false 。
输入：
["MyStack", "push", "push", "top", "pop", "empty"]
[[], [1], [2], [], [], []]
输出：
[null, null, null, 2, 2, false]

"""
import collections


class MyStack:

    def __init__(self):
        """
        Initialize your data structure here.
        """
        self.queue1 = collections.deque()
        self.queue2 = collections.deque()


    def push(self, x: int) -> None:
        """
        Push element x onto stack.
        """
        self.queue2.append(x)
        while self.queue1:
            self.queue2.append(self.queue1.popleft())
        self.queue1, self.queue2 = self.queue2, self.queue1
        # n = len(self.queue1)
        # self.queue1.append(x)
        # for _ in range(n):
        #     self.queue1.append(self.queue1.popleft())


    def pop(self) -> int:
        """
        Removes the element on top of the stack and returns that element.
        """
        return self.queue1.popleft()


    def top(self) -> int:
        """
        Get the top element.
        """
        return self.queue1[0]


    def empty(self) -> bool:
        """
        Returns whether the stack is empty.
        """
        return not self.queue1

if __name__ == '__main__':
    myStack = MyStack()
    myStack.push(1)
    myStack.push(2)
    print(myStack.top())
    print(myStack.pop())
    print(myStack.empty())