From a002be43742dbfa470b67abfa24b6dc3ca3359c3 Mon Sep 17 00:00:00 2001
From: Kanak sharma <sharmakanak043@gmail.com>
Date: Wed, 13 Nov 2024 20:48:15 +0530
Subject: [PATCH] done

---
 js/index.js | 38 ++++++++++++++++++++++++++++++++++++--
 1 file changed, 36 insertions(+), 2 deletions(-)

diff --git a/js/index.js b/js/index.js
index 59e4af7..aeb0ad9 100644
--- a/js/index.js
+++ b/js/index.js
@@ -1,6 +1,40 @@
 // Iteration 1: Names and Input
-//
-// Iteration 2: Conditionals
+let hacker1 = 'John';
+console.log("The driver's name is " + hacker1);
+let hacker2 = 'Wick';
+console.log("The navigator's name is" + hacker2);
 
+// Iteration 2: Conditionals
+if (hacker1.length > hacker2.length)
+    console.log("The driver has the longest name, it has" + hacker1.length +  "characters")
+else if (hacker2.length > hacker1.length)
+    console.log("It seems that the navigator has the longest name, it has" + hacker2.length + "characters")
+else 
+    console.log("Wow, you both have equally long names, " + hacker1.length + "characters!")
 
 // Iteration 3: Loops
+//3.1: Print all characters of the driver's name in capitals separated by a space
+let driverNameInCaps = "";
+for (let i = 0; i < hacker1.length; i++) {
+    driverNameInCaps += hacker1[i].toUpperCase();
+    if (i < hacker1.length - 1) {
+        driverNameInCaps += " ";
+    }
+}
+console.log(driverNameInCaps);
+
+//3.2:  Print all characters of the navigator's name in reverse order
+let navigatorNameReversed = "";
+for (let i = hacker2.length - 1; i >= 0; i--) {
+    navigatorNameReversed += hacker2[i];
+}
+console.log(navigatorNameReversed);
+
+//3.3: lexicographic order check
+if (hacker1 < hacker2) {
+    console.log("The driver's name goes first.");
+} else if (hacker1 > hacker2) {
+    console.log("Yo, the navigator goes first definitely.");
+} else {
+    console.log("What?! You both have the same name?");
+}
\ No newline at end of file