Leaving out terms in localization matrix? #245
wkitlasten
started this conversation in
General
Replies: 1 comment 6 replies
-
The incomplete localizer is pretty new (and therefore dangerous!). my thinking was to be conservative, any par-obs (group) pairs not included in the localizer should zero - I think this explains why your solves are faster with an incomplete localizer? Does that jive with what you are seeing? |
Beta Was this translation helpful? Give feedback.
6 replies
Sign up for free
to join this conversation on GitHub.
Already have an account?
Sign in to comment
-
Hi all, I seem to recall if a par:obs (pargp:obgnme) pair is left out of a localization matrix it will ultimately be treated as 1. For example, if the localization matrix provided only specifies obs0 is not influenced by par1 and obs1 is not influenced by par0 (below), all other obs will be influenced by all pars? Plus, obs0 and obs1 will be influenced by all other pars?
So the above would essentially be equivalent to(?):
My question arises because the parameter upgrades using the "incomplete" localization matrix seem to be significantly faster than those with the "full" (nobs:npar) localization matrix... so just wondering if I misunderstood this, or messed something else up somewhere.
Beta Was this translation helpful? Give feedback.
All reactions