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Copy path1380. Lucky Numbers in a Matrix.cpp
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1380. Lucky Numbers in a Matrix.cpp
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Given a m * n matrix of distinct numbers, return all lucky numbers in the matrix in any order.
A lucky number is an element of the matrix such that it is the minimum element in its row and maximum in its column.
Example 1:
Input: matrix = [[3,7,8],[9,11,13],[15,16,17]]
Output: [15]
Explanation: 15 is the only lucky number since it is the minimum in its row and the maximum in its column
Example 2:
Input: matrix = [[1,10,4,2],[9,3,8,7],[15,16,17,12]]
Output: [12]
Explanation: 12 is the only lucky number since it is the minimum in its row and the maximum in its column.
Example 3:
Input: matrix = [[7,8],[1,2]]
Output: [7]
Constraints:
m == mat.length
n == mat[i].length
1 <= n, m <= 50
1 <= matrix[i][j] <= 10^5.
All elements in the matrix are distinct.
class Solution {
public:
vector<int> luckyNumbers (vector<vector<int>>& matrix) {
vector<int> res;
int m=matrix.size();
int n=matrix[0].size();
vector<int> row(m, 0);
vector<int> col(n, 0);
for(int i=0;i<m;i++){
int mini=INT_MAX;
for(int j=0;j<n;j++){
if(matrix[i][j]<mini) mini=matrix[i][j];
}
row[i]=mini;
}
for(int j=0;j<n;j++){
int maxi=INT_MIN;
for(int i=0;i<m;i++){
if(matrix[i][j]>maxi) maxi=matrix[i][j];
}
col[j]=maxi;
}
for(int i=0;i<m;i++){
for(int j=0;j<n;j++){
if(matrix[i][j]==row[i] && matrix[i][j]==col[j])
res.push_back(matrix[i][j]);
}
}
return res;
}
};
// Optimized
class Solution {
public:
vector<int> luckyNumbers (vector<vector<int>>& matrix) {
vector<int> res;
int m=matrix.size();
int n=matrix[0].size();
vector<int> row(m, 0);
vector<int> col(n, 0);
for(int i=0;i<m;i++){
int mini=INT_MAX;
for(int j=0;j<n;j++){
if(matrix[i][j]<mini) mini=matrix[i][j];
}
row[i]=mini;
}
for(int j=0;j<n;j++){
int maxi=INT_MIN;
for(int i=0;i<m;i++){
if(matrix[i][j]>maxi) maxi=matrix[i][j];
}
col[j]=maxi;
}
for(int i=0;i<m;i++){
for(int j=0;j<n;j++){
if(row[i]==col[j])
res.push_back(row[i]);
}
}
return res;
}
};