Department Top Three Salaries.sql

/*
    The Employee table holds all employees. Every employee has an Id, and there is also a column for the department Id.
		+----+-------+--------+--------------+
		| Id | Name  | Salary | DepartmentId |
		+----+-------+--------+--------------+
		| 1  | Joe   | 70000  | 1            |
		| 2  | Henry | 80000  | 2            |
		| 3  | Sam   | 60000  | 2            |
		| 4  | Max   | 90000  | 1            |
		| 5  | Janet | 69000  | 1            |
		| 6  | Randy | 85000  | 1            |
		+----+-------+--------+--------------+

	The Department table holds all departments of the company.
		+----+----------+
		| Id | Name     |
		+----+----------+
		| 1  | IT       |
		| 2  | Sales    |
		+----+----------+

	Write a SQL query to find employees who earn the top three salaries in each of the department. 
    
    Link: https://leetcode.com/problems/department-top-three-salaries/

    Example: For the above tables, your SQL query should return the following rows.
		+------------+----------+--------+
		| Department | Employee | Salary |
		+------------+----------+--------+
		| IT         | Max      | 90000  |
		| IT         | Randy    | 85000  |
		| IT         | Joe      | 70000  |
		| Sales      | Henry    | 80000  |
		| Sales      | Sam      | 60000  |
		+------------+----------+--------+

    Solution: None
    
    Source: https://leetcode.com/discuss/54662/simple-solution-easy-to-understand
*/

# Write your MySQL query statement below
Select dep.Name as Department, emp.Name as Employee, emp.Salary from Department dep, 
Employee emp where emp.DepartmentId=dep.Id and 
(Select count(distinct Salary) From Employee where DepartmentId=dep.Id and Salary>emp.Salary)<3