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pool2 = nn.MaxPool1d(conved2.shape[2], self.stride) #2

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tidalmelon opened this issue Feb 6, 2024 · 0 comments
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pool2 = nn.MaxPool1d(conved2.shape[2], self.stride) #2

tidalmelon opened this issue Feb 6, 2024 · 0 comments

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@tidalmelon
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TextCNN的代码实现 池化层的stride可以不写的, 因为只会扫描一次. stride直接设置成默认值也可以.
H_out = ([seq_len-kernel_size+1] - [seq_len-kernel_size+1])/)[seq_len-kernel_size+1) +1 = 1 分子是零, stride不重要了
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