📝 💊 Add authors of repo-local writeups for break-in-ctf-2015

Author: YASME-Tim

Diff for: break-in-ctf-2015/crypto/substitution/README.md

@@ -10,6 +10,8 @@
 
 ## Write-up
 
+by [polym](https://github.com/abpolym)
+
 As the description hints, we need to substitute letters with a substitute cipher.
 
 Using these tools ([1](http://www.richkni.co.uk/php/crypta/freq.php), [2](http://crypto.interactive-maths.com/frequency-analysis-breaking-the-code.html), [3](http://www.counton.org/explorer/codebreaking/frequency-analysis.php), [4]()), we can conduct a frequency analysis:

Diff for: break-in-ctf-2015/forensic/serial_killer/README.md

@@ -18,6 +18,8 @@
 
 ## Write-up
 
+by [polym](https://github.com/abpolym)
+
 First, we extract the gzip-compressed archive using `tar xzvf SerialKillerInvestigation.tar.gz` and see that it contains a home directory of the user `berch`:
 
 ```bash

Diff for: break-in-ctf-2015/forensic/strangelmage/README.md

@@ -8,6 +8,8 @@
 
 ## Write-up
 
+by [polym](https://github.com/abpolym)
+
 We are given a JPG:
 
 ![](./stego_200.jpeg)

Diff for: break-in-ctf-2015/misc/heisenberg/README.md

@@ -12,6 +12,8 @@
 
 ## Write-up
 
+by [polym](https://github.com/abpolym)
+
 The first thing we do is googling "'Yañez Sepulveda' cipher" to get the below mentioned Origin of the cipher we have to use.
 
 After understanding what the substitute key is, we use [this code](cocaine.py) to substitute the ciphertext letters with the key letters and print out all possible combinations (since numbers and letters share the same cipher keys).