allOf through z.extend with refs / union actually anyOf

[jakobfenerparc]

Hi Sam,

amazing library, happy to see something being to actively developed.
More a question since it's not clear from the README documentation.

In the documentation it says that a z.union translates into allOf (unless globally configured to oneOf through the unionOneOf setting).
I think this should be changed to anyOf as the code suggests.

My actual question:
In my case I need to (for compatability reasons) create an allOf schema, which consists of multiple refs and some custom type.

    MySchema:
      allOf:
        - $ref: "#/components/schemas/Base1"
        - $ref: "#/components/schemas/Base2"
        - type: object
          required:
            - prop1
          properties:
            prop1:
              type: string
              description: Description1

I tried to get this by using extend as mentioned in the docs.
But the multiple refs are a problem, because when doing this:

const Base1 = z.object({ a: z.string(), b: z.number() }).openapi({ ref: "Base1" });
const Base2 = z.object({ c: z.string() }).openapi({ ref: "Base2" });
const MySchema = Base1.extend(Base2.shape).extend(z.object({ prop1: z.string() }))

I get a ref for Base1, but since .shape flattens Base2 the openapi information gets lost, so Base2 and the last z.object get merged inline into MySchema.

Is there a different way of constructing the openapi schema above (with the allOf refs) that I did not see?

[samchungy]

Ah yep you caught a mistake, I'll get onto fixing it.

Hmmm yeah that's tricky, unfortunately yeah passing in the shape means we can't infer where it came from.

#360

You could potentially use .and()?

[jakobfenerparc]

z.and works just right, thanks.
Apart from the docs, this issue solved I guess.

Thanks for !instant feedback!