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Currently to allow a user to join a different room or channel, I have to create a completely new instance of rtc-quickconnect using the new room name. Is there any way around this?
The text was updated successfully, but these errors were encountered:
What do you mean? Since every new room requires a whole RTCPeerConnection, of course you need to instantiate another rtc-quickconnect connection. What's your problem with that?
Having looked at the code, it's clear that it would be possible to do. In fact I was even considering writing it myself and contributing such a thing. But since it's clear that the project maintainers think I'm an idiot for even asking, nevermind.
Hi @IamCarbonMan - it wasn't meant to be insulting, but asking for clarification, because I was confused what you meant and whether it's even possible. If you think it's possible, you should absolutely try it! If it makes an app use less resources, then it's totally worth it!
Currently to allow a user to join a different room or channel, I have to create a completely new instance of rtc-quickconnect using the new room name. Is there any way around this?
The text was updated successfully, but these errors were encountered: