lunar_calendar.js

var CalendarData = new Array(100);
var madd = new Array(12);
var tgString = "甲乙丙丁戊己庚辛壬癸";
var dzString = "子丑寅卯辰巳午未申酉戌亥";
var numString = "一二三四五六七八九十";
var monString = "正二三四五六七八九十冬腊";
var weekString = "日一二三四五六";
var sx = "鼠牛虎兔龙蛇马羊猴鸡狗猪";
var cYear, cMonth, cDay, TheDate;
CalendarData = new Array(0xA4B, 0x5164B, 0x6A5, 0x6D4, 0x415B5, 0x2B6, 0x957, 0x2092F, 0x497, 0x60C96, 0xD4A, 0xEA5, 0x50DA9, 0x5AD, 0x2B6, 0x3126E, 0x92E, 0x7192D, 0xC95, 0xD4A, 0x61B4A, 0xB55, 0x56A, 0x4155B, 0x25D, 0x92D, 0x2192B, 0xA95, 0x71695, 0x6CA, 0xB55, 0x50AB5, 0x4DA, 0xA5B, 0x30A57, 0x52B, 0x8152A, 0xE95, 0x6AA, 0x615AA, 0xAB5, 0x4B6, 0x414AE, 0xA57, 0x526, 0x31D26, 0xD95, 0x70B55, 0x56A, 0x96D, 0x5095D, 0x4AD, 0xA4D, 0x41A4D, 0xD25, 0x81AA5, 0xB54, 0xB6A, 0x612DA, 0x95B, 0x49B, 0x41497, 0xA4B, 0xA164B, 0x6A5, 0x6D4, 0x615B4, 0xAB6, 0x957, 0x5092F, 0x497, 0x64B, 0x30D4A, 0xEA5, 0x80D65, 0x5AC, 0xAB6, 0x5126D, 0x92E, 0xC96, 0x41A95, 0xD4A, 0xDA5, 0x20B55, 0x56A, 0x7155B, 0x25D, 0x92D, 0x5192B, 0xA95, 0xB4A, 0x416AA, 0xAD5, 0x90AB5, 0x4BA, 0xA5B, 0x60A57, 0x52B, 0xA93, 0x40E95, 0x6aa, 0xad5);
madd[0] = 0;
madd[1] = 31;
madd[2] = 59;
madd[3] = 90;
madd[4] = 120;
madd[5] = 151;
madd[6] = 181;
madd[7] = 212;
madd[8] = 243;
madd[9] = 273;
madd[10] = 304;
madd[11] = 334;

function GetBit(m, n) {
    return (m >> n) & 1;
}

function e2c() {
    //使用可变参数接收传入参数，检测是否按指定规格传递日期，否则使用当前日期
    TheDate = (arguments.length != 3) ? new Date() : new Date(arguments[0], arguments[1], arguments[2]);
    var total, m, n, k;
    var isEnd = false;
    var tmp = TheDate.getYear(); //获取当前年
    if (tmp < 1900) {
        tmp += 1900;
    }
    //天数
    total = (tmp - 1921) * 365 + Math.floor((tmp - 1921) / 4) + madd[TheDate.getMonth()] + TheDate.getDate() - 38;
    //闰年加一天
    if (TheDate.getYear() % 4 == 0 && TheDate.getMonth() > 1) {
        total++;
    }
    //计算月
    //从1921年开始，对照润大小信息表（将16进制转为2进制查看，0表示小月【29天】，1表示大月【30天】）一个月一个月挨个减，直到剩下当前这个月
    for (m = 0;; m++) {
        k = (CalendarData[m] < 0xfff) ? 11 : 12;
        for (n = k; n >= 0; n--) {
            //GetBit(CalendarData[m], n)为获取第n位的二进制数值
            if (total <= 29 + GetBit(CalendarData[m], n)) {
                isEnd = true;
                break;
            }
            total = total - 29 - GetBit(CalendarData[m], n);
        }
        if (isEnd) break;
    }
    cYear = 1921 + m;
    cMonth = k - n + 1;
    cDay = total;
    if (k == 12) {
        if (cMonth == Math.floor(CalendarData[m] / 0x10000) + 1) {
            cMonth = 1 - cMonth;
        }
        if (cMonth > Math.floor(CalendarData[m] / 0x10000) + 1) {
            cMonth--;
        }
    }
}

function GetcDateString() {
    var tmp = "";
    tmp += tgString.charAt((cYear - 4) % 10);
    tmp += dzString.charAt((cYear - 4) % 12);
    tmp += "(";
    tmp += sx.charAt((cYear - 4) % 12);
    tmp += ")年 ";
    if (cMonth < 1) {
        tmp += "(闰)";
        tmp += monString.charAt(-cMonth - 1);
    } else {
        tmp += monString.charAt(cMonth - 1);
    }
    tmp += "月";
    tmp += (cDay < 11) ? "初" : ((cDay < 20) ? "十" : ((cDay < 30) ? "廿" : "三十"));
    if (cDay % 10 != 0 || cDay == 10) {
        tmp += numString.charAt((cDay - 1) % 10);
    }
    return tmp;
}

function GetLunarDay(solarYear, solarMonth, solarDay) {
    //solarYear = solarYear<1900?(1900+solarYear):solarYear;
    if (solarYear < 1921 || solarYear > 2025) {
        return "";
    } else {
        solarMonth = (parseInt(solarMonth) > 0) ? (solarMonth - 1) : 11;
        e2c(solarYear, solarMonth, solarDay);
        return GetcDateString();
    }
}

var D = new Date();
var yy = D.getFullYear();
var mm = D.getMonth() + 1;
var dd = D.getDate();
var ww = D.getDay();
var ss = parseInt(D.getTime() / 1000);
if (yy < 100) yy = "19" + yy;




function showCal(date = yy + "-" + mm + "-" + dd) {
    // document.write(GetLunarDay(yy, mm, dd));
    date = date.split("-");
    return GetLunarDay(date[0], date[1], date[2]);
}

function showDay(date = yy + "-" + mm + "-" + dd) {
    // document.write(GetLunarDay(yy, mm, dd));
    date = date.split("-");
    var day = GetLunarDay(date[0], date[1], date[2]);
    return day[day.length - 2] + day[day.length - 1];
}