CVE-2022-42475 - Heap-based Buffer Overflow in Fortinet SSL-VPN

[princechaddha]

Is there an existing template for this?

• I have searched the existing templates.

Template requests

Title: CVE-2022-42475 - Heap-based Buffer Overflow in Fortinet SSL-VPN

Description:
A heap-based buffer overflow vulnerability [CWE-122] in FortiOS SSL-VPN (versions 7.2.0 through 7.2.2, 7.0.0 through 7.0.8, 6.4.0 through 6.4.10, 6.2.0 through 6.2.11, 6.0.15 and earlier) and FortiProxy SSL-VPN (versions 7.2.0 through 7.2.1, 7.0.7 and earlier) may allow a remote unauthenticated attacker to execute arbitrary code or commands via specifically crafted requests.

Severity: Critical (CVSS 9.8)

POC:

• https://github.com/0xhaggis/CVE-2022-42475
• https://github.com/CKevens/CVE-2022-42475-RCE-POC
• https://github.com/Amir-hy/cve-2022-42475
• https://github.com/Mustafa1986/cve-2022-42475-Fortinet
• https://github.com/natceil/cve-2022-42475
• https://github.com/scrt/cve-2022-42475

References:

Fortinet Advisory

Shodan Query:

port:10443 http.favicon.hash:945408572
cpe:"cpe:2.3:o:fortinet:fortios"
http.html:"/remote/login" "xxxxxxxx"

CPE:

• cpe:2.3:o:fortinet:fortios::::::::
• cpe:2.3:a:fortinet:fortiproxy::::::::

Anything else?

No response

[princechaddha]

/bounty 200$

[algora-pbc]

💎 $200 bounty • ProjectDiscovery Bounty Available for CVE Template Contribution

Steps to Contribute:

• Claim attempt: Comment /attempt #10897 on this issue to claim attempt.
• Write the Template: Create a high-quality Nuclei template for the specified CVE, following our Contribution Guidelines and Acceptance Criteria.
• Submit the Template: Open a pull request (PR) to projectdiscovery/nuclei-templates and include /claim #10897 in the PR body to claim the bounty.
• Receive Payment: Upon successful merge of your PR, you will receive 100% of the bounty through Algora.io within 2-5 days. Ensure you are eligible for payouts.

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Attempt	Started (GMT+0)	Solution
🔴 @rogueloop	Oct 5, 2024, 6:38:37 AM	WIP
🔴 @anuj846k	Oct 5, 2024, 9:32:21 AM	WIP
🔴 @charlesmigel	Dec 12, 2024, 9:05:25 AM	WIP

[rogueloop]

/attempt #10897

Algora profile	Completed bounties	Tech	Active attempts	Options
@rogueloop	1 bounty from 1 project	Java, C, JavaScript & more		Cancel attempt

[anuj846k]

/attempt #10897

Options

• Cancel my attempt

[algora-pbc]

Note

The user @rogueloop is already attempting to complete issue #10897 and claim the bounty. We recommend checking in on @rogueloop's progress, and potentially collaborating, before starting a new solution.

[sec13b]

http/exposed-panels/fortinet/fortios-panel.yaml

[algora-pbc]

@rogueloop: Reminder that in 4 days the bounty will become up for grabs, so please submit a pull request before then 🙏

[sec13b]

I think is impossible to make template for this cve , the base address of libc is hard coded.
rdi ,cmd,asdf these offsets are in libc and you dont know them , any device have another base address (i think),

all base address are copied from all cve exploit (POC) you find on github are copied from scrt .

POC

    https://github.com/0xhaggis/CVE-2022-42475
    https://github.com/CKevens/CVE-2022-42475-RCE-POC
    https://github.com/Amir-hy/cve-2022-42475
    https://github.com/Mustafa1986/cve-2022-42475-Fortinet
    https://github.com/natceil/cve-2022-42475
    https://github.com/scrt/cve-2022-42475   *

base address
#hardcoded value which would probably need to be bruteforced or leaked

rdi = p64(hardcoded + 0xc48)
cmd = p64(hardcoded + 0xd38)
asdf = hardcoded + 0xd38

scrt he did not offer any explanation at "Question about libc offset (0xc48 and 0xd38)" to the question asked by mekhalleh

[algora-pbc]

@anuj846k: Reminder that in 4 days the bounty will become up for grabs, so please submit a pull request before then 🙏

[algora-pbc]

The bounty is up for grabs! Everyone is welcome to /attempt #10897 🙌

[charlesmigel]

/attempt #10897

Options

• Cancel my attempt

[algora-pbc]

@charlesmigel: Reminder that in 4 days the bounty will become up for grabs, so please submit a pull request before then 🙏

[algora-pbc]

The bounty is up for grabs! Everyone is welcome to /attempt #10897 🙌