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chore: move pom parser to parsers module
Signed-off-by: Ben Selwyn-Smith <[email protected]>
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# Copyright (c) 2024 - 2024, Oracle and/or its affiliates. All rights reserved. | ||
# Licensed under the Universal Permissive License v 1.0 as shown at https://oss.oracle.com/licenses/upl/. | ||
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"""This module contains the parser for POM files.""" | ||
import logging | ||
from xml.etree.ElementTree import Element # nosec | ||
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import defusedxml.ElementTree | ||
from defusedxml.ElementTree import fromstring | ||
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logger: logging.Logger = logging.getLogger(__name__) | ||
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def parse_pom_string(pom_string: str) -> Element | None: | ||
""" | ||
Parse the passed POM string using defusedxml. | ||
Parameters | ||
---------- | ||
pom_string : str | ||
The contents of a POM file as a string. | ||
Returns | ||
------- | ||
Element | None | ||
The parsed element representing the POM's XML hierarchy. | ||
""" | ||
try: | ||
# Stored here first to help with type checking. | ||
pom: Element = fromstring(pom_string) | ||
return pom | ||
except defusedxml.ElementTree.ParseError as error: | ||
logger.debug("Failed to parse XML: %s", error) | ||
return None |
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