a.py

number = 952  # Assume this is the input number, change it to other values to test your code

# Exercise 1: Given a 3 digit number, print the digit in the first position (from the left - the hundreds digit).

# Solution 1:
hundreds = number / 100  # hundreds = 3.47
hundreds = int(hundreds)  # hundreds = 3
print(hundreds)

# Solution 2 - Using the number as a string
str_number = str(number)
print(str_number[0])

# Solution 3 - Modulo
remainder = number % 100  # remainder = 47
hundreds = number - remainder  # hundreds = 300
hundreds = hundreds / 100  # hundreds = 3.0
hundreds = int(hundreds)  # hundreds = 3
print(hundreds)


# Exercise 2: Given a 3 digit number, print the digit in the second position (from the left - the tens digit).

# Solution 1
hundreds = number / 100  # hundreds = 3.47
hundreds = int(hundreds)  # hundreds = 3
hundreds = hundreds * 10  # hundreds = 30
new_number = number / 10  # new_number = 34.7
new_number = int(new_number)  # new_number = 34
print(new_number - hundreds)  # 34 - 30 = 4

# Solution 2 - same as solution 1 but in one line
print(int(number / 10) - int(number / 100) * 10)

# Solution 3 - Using the number as a string
str_number = str(number)
print(str_number[1])

# Solution 4 - Modulo
remainder = number % 100  # remainder = 47
ones = remainder % 10  # ones = 7
tens = remainder - ones  # tens = 40
tens = tens / 10  # tens = 4.0
tens = int(tens)  # tens = 4
print(tens)

# INPUT = three values (numbers), OUTPUT = sum and average.
a = 3
b = 4
c = 5
print(a + b + c)  # SUM = 12
print((a + b + c) / 3)  # AVERAGE = 4.0

# INPUT = width and length of a rectangle room, OUTPUT = area and perimeter.
width = 3
length = 4
print(width * length)  # AREA = 12
print((width + length) * 2)  # PERIMETER = 14

# INPUT = diameter and depth of a pot, OUTPUT = volume.
diameter = 3
depth = 4
radius = diameter / 2
print(3.14 * radius * radius * depth)  # VOLUME ~= 28.26

# INPUT = 4 digit number (1000-9999), OUTPUT = the "ones" digit.
number = 1234
print(number % 10)  # ONES = 4

# INPUT = 4 digit number (1000-9999), OUTPUT = the "tens" digit.
number = 1234
print((number % 100) // 10)  # TENS = 3

# INPUT = 3 digit number (100-999), OUTPUT = the "hundreds" digit.
number = 123
print((number % 1000) // 100)  # HUNDREDS = 1

# INPUT = 2 digit number (10-99), OUTPUT = sum of the digits.
number = 12
ones = number % 10
tens = (number % 100) // 10
print(ones + tens)  # SUM = 3

# INPUT = 2 digit number (10-99), OUTPUT = reverse order of the digits.
number = 12
ones = number % 10
tens = (number % 100) // 10
print(ones * 10 + tens)  # REVERSE = 21