Output only one file not all folder in output folder

[daidaiV5]

Hello:

I would like to output only one file not all folder in output folder

for example :

process a {
 publishDir path: './resultat' 
 echo true

 output:
 file("a/**/2.txt") into found

"""
mkdir -p a/a b/b c/c
touch a/1.txt
touch b/1.txt
touch c/1.txt
touch a/a/2.txt
touch b/b/2.txt
touch c/c/2.txt
"""   }

Now I output a folder in folder ‘resultat’: ./resultat/a/a/2.txt, but I only want to output '2.txt' in the folder ‘resultat’ : ./resultat/2.txt
How to do that?

Thanks for taking the time to read.

[pditommaso]

use output: file('a/a/2.txt') instead of **

[daidaiV5]

thanks for your reply, but it's not my question, I can output the file 'a/a/2.txt', but I would like only a file not a folder. because even I use output: file('a/a/2.txt'), The results are: '/resultat/a/a/2.txt', but I only want to output '2.txt' in the folder ‘resultat’ : it should like ./resultat/2.txt

[pditommaso]

This may help https://github.com/nextflow-io/patterns/blob/master/docs/publish-rename-outputs.adoc

[daidaiV5]

thanks a lot, I see in link is 'Save outputs in a sub-directory', but I would like to bring the file out of sub-directory and store in directory not sub-directory, if I found the solution, I will complete here.