From 4265d28e3c65c0ffd6c92540e09c49be3a5a6da7 Mon Sep 17 00:00:00 2001
From: koohong <41971787+koohong@users.noreply.github.com>
Date: Fri, 5 Jan 2024 11:59:53 -0800
Subject: [PATCH] Update 2.md

---
 _problems/unit-02/E-cdf-of-a-continuous-rv/2.md | 6 +-----
 1 file changed, 1 insertion(+), 5 deletions(-)

diff --git a/_problems/unit-02/E-cdf-of-a-continuous-rv/2.md b/_problems/unit-02/E-cdf-of-a-continuous-rv/2.md
index 4b2abe9..f08b68d 100644
--- a/_problems/unit-02/E-cdf-of-a-continuous-rv/2.md
+++ b/_problems/unit-02/E-cdf-of-a-continuous-rv/2.md
@@ -5,8 +5,4 @@ statement: |
 ---
 
 Sol:
-Given CDF, we can find its pdf as shown below.
-
-$$\frac{d}{dx}[e^{\frac{-1}{x}}]=\frac{e^{frac{-1}{x}{x^2}}$$ 
-
-and $\int_{0}^{\inf}\frac{e^{frac{-1}{x}{x^2}}dx=1$
+Given CDF, we can find its pdf by $\frac{d}{dx}[e^{\frac{-1}{x}}]=\frac{e^{frac{-1}{x}{x^2}}$ and $\int_{0}^{\inf}\frac{e^{frac{-1}{x}{x^2}}dx=1$