38_count_and_say.py

class Solution:
    def countAndSay(self, n: int) -> str:

        def read(string: str) -> str:
            tmp = ''
            num = 0
            ans = ''
            for i in range(0, len(string)):
                if string[i] == tmp:
                    num += 1
                else:
                    if i != 0:
                        ans = ans + str(num) + tmp
                    tmp = string[i]
                    num = 1
            ans = ans + str(num) + tmp
            return ans
        
        ans = '1'
        for i in range(n-1):
            ans = read(ans)
        return ans

'''
    This is my personal record of solving Leetcode Problems. 
    If you have any questions, please discuss them in [Issues](https://github.com/mengxinayan/leetcode/issues).
    Copyright (C) 2020-2022  mengxinayan

    This program is free software: you can redistribute it and/or modify
    it under the terms of the GNU General Public License as published by
    the Free Software Foundation, either version 3 of the License, or
    (at your option) any later version.

    This program is distributed in the hope that it will be useful,
    but WITHOUT ANY WARRANTY; without even the implied warranty of
    MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.  See the
    GNU General Public License for more details.

    You should have received a copy of the GNU General Public License
    along with this program.  If not, see <http://www.gnu.org/licenses/>.
'''