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* Adding doctests and changing file name * [pre-commit.ci] auto fixes from pre-commit.com hooks for more information, see https://pre-commit.ci * Update binary_multiplication.py * [pre-commit.ci] auto fixes from pre-commit.com hooks for more information, see https://pre-commit.ci * Update binary_multiplication.py * Changing comment and changing name function * Changing comment and changing name function * [pre-commit.ci] auto fixes from pre-commit.com hooks for more information, see https://pre-commit.ci * Update binary_multiplication.py * [pre-commit.ci] auto fixes from pre-commit.com hooks for more information, see https://pre-commit.ci * Update binary_multiplication.py * Update binary_multiplication.py --------- Co-authored-by: pre-commit-ci[bot] <66853113+pre-commit-ci[bot]@users.noreply.github.com> Co-authored-by: Tianyi Zheng <[email protected]>
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""" | ||
Binary Multiplication | ||
This is a method to find a*b in a time complexity of O(log b) | ||
This is one of the most commonly used methods of finding result of multiplication. | ||
Also useful in cases where solution to (a*b)%c is required, | ||
where a,b,c can be numbers over the computers calculation limits. | ||
Done using iteration, can also be done using recursion | ||
Let's say you need to calculate a * b | ||
RULE 1 : a * b = (a+a) * (b/2) ---- example : 4 * 4 = (4+4) * (4/2) = 8 * 2 | ||
RULE 2 : IF b is odd, then ---- a * b = a + (a * (b - 1)), where (b - 1) is even. | ||
Once b is even, repeat the process to get a * b | ||
Repeat the process until b = 1 or b = 0, because a*1 = a and a*0 = 0 | ||
As far as the modulo is concerned, | ||
the fact : (a+b) % c = ((a%c) + (b%c)) % c | ||
Now apply RULE 1 or 2, whichever is required. | ||
@author chinmoy159 | ||
""" | ||
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def binary_multiply(a: int, b: int) -> int: | ||
""" | ||
Multiply 'a' and 'b' using bitwise multiplication. | ||
Parameters: | ||
a (int): The first number. | ||
b (int): The second number. | ||
Returns: | ||
int: a * b | ||
Examples: | ||
>>> binary_multiply(2, 3) | ||
6 | ||
>>> binary_multiply(5, 0) | ||
0 | ||
>>> binary_multiply(3, 4) | ||
12 | ||
>>> binary_multiply(10, 5) | ||
50 | ||
>>> binary_multiply(0, 5) | ||
0 | ||
>>> binary_multiply(2, 1) | ||
2 | ||
>>> binary_multiply(1, 10) | ||
10 | ||
""" | ||
res = 0 | ||
while b > 0: | ||
if b & 1: | ||
res += a | ||
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a += a | ||
b >>= 1 | ||
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return res | ||
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def binary_mod_multiply(a: int, b: int, modulus: int) -> int: | ||
""" | ||
Calculate (a * b) % c using binary multiplication and modular arithmetic. | ||
Parameters: | ||
a (int): The first number. | ||
b (int): The second number. | ||
modulus (int): The modulus. | ||
Returns: | ||
int: (a * b) % modulus. | ||
Examples: | ||
>>> binary_mod_multiply(2, 3, 5) | ||
1 | ||
>>> binary_mod_multiply(5, 0, 7) | ||
0 | ||
>>> binary_mod_multiply(3, 4, 6) | ||
0 | ||
>>> binary_mod_multiply(10, 5, 13) | ||
11 | ||
>>> binary_mod_multiply(2, 1, 5) | ||
2 | ||
>>> binary_mod_multiply(1, 10, 3) | ||
1 | ||
""" | ||
res = 0 | ||
while b > 0: | ||
if b & 1: | ||
res = ((res % modulus) + (a % modulus)) % modulus | ||
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a += a | ||
b >>= 1 | ||
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return res | ||
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if __name__ == "__main__": | ||
import doctest | ||
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doctest.testmod() |