diff --git a/algorithms/001718-construct-the-lexicographically-largest-valid-sequence/README.md b/algorithms/001718-construct-the-lexicographically-largest-valid-sequence/README.md
new file mode 100644
index 000000000..83973b856
--- /dev/null
+++ b/algorithms/001718-construct-the-lexicographically-largest-valid-sequence/README.md
@@ -0,0 +1,110 @@
+1718\. Construct the Lexicographically Largest Valid Sequence
+
+**Difficulty:** Medium
+
+**Topics:** `Array`, `Backtracking`
+
+Given an integer `n`, find a sequence that satisfies all of the following:
+
+- The integer `1` occurs once in the sequence.
+- Each integer between `2` and `n` occurs twice in the sequence.
+- For every integer `i` between `2` and `n`, the **distance** between the two occurrences of `i` is exactly `i`.
+
+The **distance** between two numbers on the sequence, `a[i]` and `a[j]`, is the absolute difference of their indices, `|j - i|`.
+
+Return _the **lexicographically largest** sequence. It is guaranteed that under the given constraints, there is always a solution_.
+
+A sequence `a` is lexicographically larger than a sequence `b` (of the same length) if in the first position where `a` and `b` differ, sequence `a` has a number greater than the corresponding number in `b`. For example, `[0,1,9,0]` is lexicographically larger than `[0,1,5,6]` because the first position they differ is at the third number, and `9` is greater than `5`.
+
+**Example 1:**
+
+- **Input:** n = 3
+- **Output:** [3,1,2,3,2]
+- **Explanation:** [2,3,2,1,3] is also a valid sequence, but [3,1,2,3,2] is the lexicographically largest valid sequence.
+
+**Example 2:**
+
+- **Input:** n = 5
+- **Output:** [5,3,1,4,3,5,2,4,2]
+
+
+
+**Constraints:**
+
+- `1 <= n <= 20`
+
+
+**Hint:**
+1. Heuristic algorithm may work.
+
+
+
+**Solution:**
+
+We need to construct the lexicographically largest valid sequence that satisfies specific constraints. The sequence must include the integer 1 once and each integer from 2 to n exactly twice, with the distance between their occurrences equal to their value.
+
+### Approach
+The approach uses a backtracking algorithm to build the sequence step-by-step, ensuring that each number is placed in the highest possible position to achieve the lexicographically largest sequence. The key steps are:
+
+1. **Track Usage and Reservations**: Use arrays to track which numbers have been used and their positions, and which positions are reserved for subsequent occurrences of a number.
+2. **Backtracking**: Recursively attempt to place each number starting from the largest possible value (n) down to 1. This ensures that the lexicographically largest sequence is found first.
+3. **Reserve Positions**: When placing the first occurrence of a number, reserve the position where the second occurrence must be placed. This ensures the correct distance between the two occurrences.
+
+Let's implement this solution in PHP: **[1718. Construct the Lexicographically Largest Valid Sequence](https://github.com/mah-shamim/leet-code-in-php/tree/main/algorithms/001718-construct-the-lexicographically-largest-valid-sequence/solution.php)**
+
+```php
+<?php
+/**
+ * @param Integer $n
+ * @return Integer[]
+ */
+function constructDistancedSequence($n) {
+    ...
+    ...
+    ...
+    /**
+     * go to ./solution.php
+     */
+}
+
+/**
+ * @param $current_pos
+ * @param $sequence
+ * @param $used
+ * @param $reserved
+ * @param $n
+ * @return bool
+ */
+function backtrack($current_pos, &$sequence, &$used, &$reserved, $n) {
+    ...
+    ...
+    ...
+    /**
+     * go to ./solution.php
+     */
+}
+
+// Test cases
+print_r(constructDistancedSequence(3));
+print_r(constructDistancedSequence(5));
+?>
+```
+
+### Explanation:
+
+1. **Initialization**: The `constructLargestValidSequence` function initializes the necessary arrays and starts the backtracking process from position 0.
+2. **Backtracking Function**: The `backtrack` function handles placing numbers in the sequence:
+   - If the current position is reserved, it places the required number and checks if the rest of the sequence can be filled.
+   - If not reserved, it tries placing numbers from n down to 1, ensuring the largest possible number is placed first.
+   - For each number, it checks if the next occurrence can be placed at the correct reserved position, ensuring the distance constraint is met.
+
+This approach efficiently explores possible sequences while ensuring the lexicographically largest valid sequence is found first.
+
+**Contact Links**
+
+If you found this series helpful, please consider giving the **[repository](https://github.com/mah-shamim/leet-code-in-php)** a star on GitHub or sharing the post on your favorite social networks 😍. Your support would mean a lot to me!
+
+If you want more helpful content like this, feel free to follow me:
+
+- **[LinkedIn](https://www.linkedin.com/in/arifulhaque/)**
+- **[GitHub](https://github.com/mah-shamim)**
\ No newline at end of file
diff --git a/algorithms/001718-construct-the-lexicographically-largest-valid-sequence/solution.php b/algorithms/001718-construct-the-lexicographically-largest-valid-sequence/solution.php
new file mode 100644
index 000000000..295d3b51e
--- /dev/null
+++ b/algorithms/001718-construct-the-lexicographically-largest-valid-sequence/solution.php
@@ -0,0 +1,89 @@
+<?php
+
+class Solution {
+
+    /**
+     * @param Integer $n
+     * @return Integer[]
+     */
+    function constructDistancedSequence($n) {
+        $length = 2 * $n - 1;
+        $sequence = array_fill(0, $length, 0);
+        $used = array_fill(0, $n + 1, 0); // used[0] unused
+        $reserved = array_fill(0, $length, null);
+
+        $success = $this->backtrack(0, $sequence, $used, $reserved, $n);
+
+        return $success ? $sequence : [];
+    }
+
+    /**
+     * @param $current_pos
+     * @param $sequence
+     * @param $used
+     * @param $reserved
+     * @param $n
+     * @return bool
+     */
+    function backtrack($current_pos, &$sequence, &$used, &$reserved, $n) {
+        $length = 2 * $n - 1;
+        if ($current_pos >= $length) {
+            return true;
+        }
+
+        if ($sequence[$current_pos] != 0) {
+            return $this->backtrack($current_pos + 1, $sequence, $used, $reserved, $n);
+        }
+
+        if ($reserved[$current_pos] !== null) {
+            $num = $reserved[$current_pos];
+            if ($used[$num] != 1) {
+                return false;
+            }
+            // Place the second occurrence
+            $sequence[$current_pos] = $num;
+            $used[$num] = 2;
+            $success = $this->backtrack($current_pos + 1, $sequence, $used, $reserved, $n);
+            if ($success) {
+                return true;
+            } else {
+                $sequence[$current_pos] = 0;
+                $used[$num] = 1;
+                return false;
+            }
+        } else {
+            // Try placing numbers from n down to 1
+            for ($num = $n; $num >= 1; $num--) {
+                if ($num == 1) {
+                    if ($used[1] == 0) {
+                        $sequence[$current_pos] = 1;
+                        $used[1] = 1;
+                        $success = $this->backtrack($current_pos + 1, $sequence, $used, $reserved, $n);
+                        if ($success) {
+                            return true;
+                        }
+                        $sequence[$current_pos] = 0;
+                        $used[1] = 0;
+                    }
+                } else {
+                    if ($used[$num] == 0) {
+                        $next_pos = $current_pos + $num;
+                        if ($next_pos < $length && $sequence[$next_pos] == 0 && $reserved[$next_pos] === null) {
+                            $sequence[$current_pos] = $num;
+                            $used[$num] = 1;
+                            $reserved[$next_pos] = $num;
+                            $success = $this->backtrack($current_pos + 1, $sequence, $used, $reserved, $n);
+                            if ($success) {
+                                return true;
+                            }
+                            $sequence[$current_pos] = 0;
+                            $used[$num] = 0;
+                            $reserved[$next_pos] = null;
+                        }
+                    }
+                }
+            }
+            return false;
+        }
+    }
+}
\ No newline at end of file