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id="content-inner"><div class="recent-posts" id="recent-posts"><div class="recent-post-item"><div class="post_cover left_radius"><a href="/2020/12/lqxsw-meiguihaian/" title="《玫瑰海岸》 摘抄"> <img class="post_bg" src="https://cdn.jsdelivr.net/gh/lemonaaaaa/CDN2/img/covers/meiguihaian.jpg" onerror="this.onerror=null;this.src='https://cdn.jsdelivr.net/gh/lemonaaaaa/CDN/img/404.jpg'" alt="《玫瑰海岸》 摘抄"></a></div><div class="recent-post-info"><a class="article-title" href="/2020/12/lqxsw-meiguihaian/" title="《玫瑰海岸》 摘抄">《玫瑰海岸》 摘抄</a><div class="article-meta-wrap"><time class="post-meta__date" title="发表于 2020-12-30 14:11:06"><i class="fa fa-calendar" aria-hidden="true"></i>2020-12-30</time><span class="article-meta"><span class="article-meta__separator">|</span><i class="fa fa-inbox article-meta__icon" aria-hidden="true"></i><a class="article-meta__categories" href="/categories/%E6%96%87%E5%AD%A6/">文学</a><i class="fa fa-angle-right" aria-hidden="true"></i><i class="fa fa-inbox article-meta__icon" aria-hidden="true"></i><a class="article-meta__categories" href="/categories/%E6%96%87%E5%AD%A6/%E6%95%A3%E6%96%87/">散文</a></span></div><div class="content"> 海岸小品
谛听那涛声
有时候在海边的黄昏，看海鸥以优雅闲淡的姿势飞过，很容易忘记它们飞行是为了觅食；因为在我们的想象里，觅食是一种紧张的行为，应该是匆忙而混乱的。
静静看海鸥划过晚霞，我感觉它们像我们一样，是来欣赏最后的日落。或者竟以一种澄明贞静的心情谛听着海潮的声音，让浪一波一波地冲刷着心的礁 ...</div></div></div><div class="recent-post-item"><div class="post_cover right_radius"><a href="/2020/09/ccf-csp-202009/" title="第二十次CCF计算机软件能力认证 (CCF CSP 202009) 题解"> <img class="post_bg" src="https://cdn.jsdelivr.net/gh/lemonaaaaa/CDN2/img/covers/ccf-csp.jpg" onerror="this.onerror=null;this.src='https://cdn.jsdelivr.net/gh/lemonaaaaa/CDN/img/404.jpg'" alt="第二十次CCF计算机软件能力认证 (CCF CSP 202009) 题解"></a></div><div class="recent-post-info"><a class="article-title" href="/2020/09/ccf-csp-202009/" title="第二十次CCF计算机软件能力认证 (CCF CSP 202009) 题解">第二十次CCF计算机软件能力认证 (CCF CSP 202009) 题解</a><div class="article-meta-wrap"><time class="post-meta__date" title="发表于 2020-09-15 19:53:57"><i class="fa fa-calendar" aria-hidden="true"></i>2020-09-15</time><span class="article-meta"><span class="article-meta__separator">|</span><i class="fa fa-inbox article-meta__icon" aria-hidden="true"></i><a class="article-meta__categories" href="/categories/Code-life/">Code life</a><i class="fa fa-angle-right" aria-hidden="true"></i><i class="fa fa-inbox article-meta__icon" aria-hidden="true"></i><a class="article-meta__categories" href="/categories/Code-life/CCF-CSP/">CCF CSP</a></span></div><div class="content"> 第一题
题目大意
给出一个参考点，再给出nnn个点，求这nnn个点中距参考点欧几里得最近的333个点的编号。如果距离相同，则按照编号升序排序。
解法
直接求出每个点距离参考点的距离，再排序即可。
如果不会排序，则扫三遍距离，每次找不同并且最小的即可。
代码
12345678910111213 ...</div></div></div><div class="recent-post-item"><div class="post_cover left_radius"><a href="/2020/08/luogu-4015/" title="洛谷 P4015 运输问题 题解"> <img class="post_bg" src="https://cdn.jsdelivr.net/gh/lemonaaaaa/CDN/img/luogu_default_cover.png" onerror="this.onerror=null;this.src='https://cdn.jsdelivr.net/gh/lemonaaaaa/CDN/img/404.jpg'" alt="洛谷 P4015 运输问题 题解"></a></div><div class="recent-post-info"><a class="article-title" href="/2020/08/luogu-4015/" title="洛谷 P4015 运输问题 题解">洛谷 P4015 运输问题 题解</a><div class="article-meta-wrap"><time class="post-meta__date" title="发表于 2020-08-28 16:06:31"><i class="fa fa-calendar" aria-hidden="true"></i>2020-08-28</time><span class="article-meta"><span class="article-meta__separator">|</span><i class="fa fa-inbox article-meta__icon" aria-hidden="true"></i><a class="article-meta__categories" href="/categories/Code-life/">Code life</a><i class="fa fa-angle-right" aria-hidden="true"></i><i class="fa fa-inbox article-meta__icon" aria-hidden="true"></i><a class="article-meta__categories" href="/categories/Code-life/Luogu/">Luogu</a></span></div><div class="content">
题目链接
题目大意
WWW 公司有 mmm 个仓库和 nnn 个零售商店。第 iii 个仓库有 aia_iai 个单位的货物；第 jjj 个零售商店需要 bjb_jbj 个单位的货物。
货物供需平衡.
从第 iii 个仓库运送每单位货物到第 jjj 个零售商店的费用为 cijc_{ij} ...</div></div></div><div class="recent-post-item"><div class="post_cover right_radius"><a href="/2020/08/luogu-2596/" title="洛谷 P2596 [ZJOI2006]书架 题解"> <img class="post_bg" src="https://cdn.jsdelivr.net/gh/lemonaaaaa/CDN/img/luogu_default_cover.png" onerror="this.onerror=null;this.src='https://cdn.jsdelivr.net/gh/lemonaaaaa/CDN/img/404.jpg'" alt="洛谷 P2596 [ZJOI2006]书架 题解"></a></div><div class="recent-post-info"><a class="article-title" href="/2020/08/luogu-2596/" title="洛谷 P2596 [ZJOI2006]书架 题解">洛谷 P2596 [ZJOI2006]书架 题解</a><div class="article-meta-wrap"><time class="post-meta__date" title="发表于 2020-08-27 20:48:14"><i class="fa fa-calendar" aria-hidden="true"></i>2020-08-27</time><span class="article-meta"><span class="article-meta__separator">|</span><i class="fa fa-inbox article-meta__icon" aria-hidden="true"></i><a class="article-meta__categories" href="/categories/Code-life/">Code life</a><i class="fa fa-angle-right" aria-hidden="true"></i><i class="fa fa-inbox article-meta__icon" aria-hidden="true"></i><a class="article-meta__categories" href="/categories/Code-life/Luogu/">Luogu</a></span></div><div class="content">
题目链接
题目原文
小 T 有一个很大的书柜。这个书柜的构造有些独特，即书柜里的书是从上至下堆放成一列。她用 111 到 nnn 的正整数给每本书都编了号。
小 T 在看书的时候，每次取出一本书，看完后放回书柜然后再拿下一本。由于这些书太有吸引力了，所以她看完后常常会忘记原来是放在书柜的什么位 ...</div></div></div><div class="recent-post-item"><div class="post_cover left_radius"><a href="/2020/08/bomb-lab/" title="计算机系统基础 Bomb Lab 实验"> <img class="post_bg" src="https://cdn.jsdelivr.net/gh/lemonaaaaa/CDN/img/essay/bomb-lab/cover.jpg" onerror="this.onerror=null;this.src='https://cdn.jsdelivr.net/gh/lemonaaaaa/CDN/img/404.jpg'" alt="计算机系统基础 Bomb Lab 实验"></a></div><div class="recent-post-info"><a class="article-title" href="/2020/08/bomb-lab/" title="计算机系统基础 Bomb Lab 实验">计算机系统基础 Bomb Lab 实验</a><div class="article-meta-wrap"><time class="post-meta__date" title="发表于 2020-08-26 13:33:06"><i class="fa fa-calendar" aria-hidden="true"></i>2020-08-26</time><span class="article-meta"><span class="article-meta__separator">|</span><i class="fa fa-inbox article-meta__icon" aria-hidden="true"></i><a class="article-meta__categories" href="/categories/Code-life/">Code life</a><i class="fa fa-angle-right" aria-hidden="true"></i><i class="fa fa-inbox article-meta__icon" aria-hidden="true"></i><a class="article-meta__categories" href="/categories/Code-life/System/">System</a></span></div><div class="content"> phase_6
123456789101112131415161718192021222324252627282930313233343536373839404142434445464748495051525354555657585960616263646566676869707172737475 ...</div></div></div><div class="recent-post-item"><div class="post_cover right_radius"><a href="/2020/08/educational-codeforces-round-94-div2/" title="Educational Codeforces Round 94 (Rated for Div. 2) 题解"> <img class="post_bg" src="https://cdn.jsdelivr.net/gh/lemonaaaaa/CDN2/img/codeforces/covers/edu-round-94.png" onerror="this.onerror=null;this.src='https://cdn.jsdelivr.net/gh/lemonaaaaa/CDN/img/404.jpg'" alt="Educational Codeforces Round 94 (Rated for Div. 2) 题解"></a></div><div class="recent-post-info"><a class="article-title" href="/2020/08/educational-codeforces-round-94-div2/" title="Educational Codeforces Round 94 (Rated for Div. 2) 题解">Educational Codeforces Round 94 (Rated for Div. 2) 题解</a><div class="article-meta-wrap"><time class="post-meta__date" title="发表于 2020-08-26 13:31:59"><i class="fa fa-calendar" aria-hidden="true"></i>2020-08-26</time><span class="article-meta"><span class="article-meta__separator">|</span><i class="fa fa-inbox article-meta__icon" aria-hidden="true"></i><a class="article-meta__categories" href="/categories/Code-life/">Code life</a><i class="fa fa-angle-right" aria-hidden="true"></i><i class="fa fa-inbox article-meta__icon" aria-hidden="true"></i><a class="article-meta__categories" href="/categories/Code-life/Codeforces/">Codeforces</a><i class="fa fa-angle-right" aria-hidden="true"></i><i class="fa fa-inbox article-meta__icon" aria-hidden="true"></i><a class="article-meta__categories" href="/categories/Code-life/Codeforces/Round/">Round</a></span></div><div class="content"> A. String Similarity
题目链接
题目原文
题目大意
定义两个字符串相似：两个字符串中至少有一个位置的值相同。
现在给出一个长度为2n−12n-12n−1的字符串sss，现在让你构造一个长度为nnn的字符串，使得这个字符串与sss的所有长度为nnn的子串都相似。
解题 ...</div></div></div><div class="recent-post-item"><div class="post_cover left_radius"><a href="/2020/08/codeforces-round-665-div2/" title="Codeforces Round 665 (Div. 2) 题解"> <img class="post_bg" src="https://cdn.jsdelivr.net/gh/lemonaaaaa/CDN2/img/codeforces/covers/round-665.png" onerror="this.onerror=null;this.src='https://cdn.jsdelivr.net/gh/lemonaaaaa/CDN/img/404.jpg'" alt="Codeforces Round 665 (Div. 2) 题解"></a></div><div class="recent-post-info"><a class="article-title" href="/2020/08/codeforces-round-665-div2/" title="Codeforces Round 665 (Div. 2) 题解">Codeforces Round 665 (Div. 2) 题解</a><div class="article-meta-wrap"><time class="post-meta__date" title="发表于 2020-08-22 20:24:38"><i class="fa fa-calendar" aria-hidden="true"></i>2020-08-22</time><span class="article-meta"><span class="article-meta__separator">|</span><i class="fa fa-inbox article-meta__icon" aria-hidden="true"></i><a class="article-meta__categories" href="/categories/Code-life/">Code life</a><i class="fa fa-angle-right" aria-hidden="true"></i><i class="fa fa-inbox article-meta__icon" aria-hidden="true"></i><a class="article-meta__categories" href="/categories/Code-life/Codeforces/">Codeforces</a><i class="fa fa-angle-right" aria-hidden="true"></i><i class="fa fa-inbox article-meta__icon" aria-hidden="true"></i><a class="article-meta__categories" href="/categories/Code-life/Codeforces/Round/">Round</a></span></div><div class="content"> A. Distance and Axis
题目链接
题目原文
题目大意
在OXOXOX轴上，给出点AAA的坐标x=nx=nx=n，给出一个值kkk，求问能不能在OXOXOX轴上找一个点BBB，使得你∣OA−AB∣=k|OA-AB|=k∣OA−AB∣=k。如果不能找到，你每次可以将AAA点 ...</div></div></div><div class="recent-post-item"><div class="post_cover right_radius"><a href="/2020/08/educational-codeforces-round-93-div2/" title="Educational Codeforces Round 93 (Rated for Div. 2) 题解"> <img class="post_bg" src="https://cdn.jsdelivr.net/gh/lemonaaaaa/CDN2/img/codeforces/covers/edu-round-93.png" onerror="this.onerror=null;this.src='https://cdn.jsdelivr.net/gh/lemonaaaaa/CDN/img/404.jpg'" alt="Educational Codeforces Round 93 (Rated for Div. 2) 题解"></a></div><div class="recent-post-info"><a class="article-title" href="/2020/08/educational-codeforces-round-93-div2/" title="Educational Codeforces Round 93 (Rated for Div. 2) 题解">Educational Codeforces Round 93 (Rated for Div. 2) 题解</a><div class="article-meta-wrap"><time class="post-meta__date" title="发表于 2020-08-15 21:46:33"><i class="fa fa-calendar" aria-hidden="true"></i>2020-08-15</time><span class="article-meta"><span class="article-meta__separator">|</span><i class="fa fa-inbox article-meta__icon" aria-hidden="true"></i><a class="article-meta__categories" href="/categories/Code-life/">Code life</a><i class="fa fa-angle-right" aria-hidden="true"></i><i class="fa fa-inbox article-meta__icon" aria-hidden="true"></i><a class="article-meta__categories" href="/categories/Code-life/Codeforces/">Codeforces</a><i class="fa fa-angle-right" aria-hidden="true"></i><i class="fa fa-inbox article-meta__icon" aria-hidden="true"></i><a class="article-meta__categories" href="/categories/Code-life/Codeforces/Round/">Round</a></span></div><div class="content"> A. Bad Triangle
题目链接
题目原文
题目大意
给出n条边，每条边有一个长度，求问是否存在3条边不能构成三角形。
解题思路
最开始看错题了，以为是是否存在3条边能构成三角形，结果又一次10分钟没切掉A.
直接判断最小的两条边边长之和是否小于等于最长的边的边长即可。
解法 ...</div></div></div><div class="recent-post-item"><div class="post_cover left_radius"><a href="/2020/08/codeforces-round-664-div2/" title="Codeforces Round 664 (Div. 2) 题解"> <img class="post_bg" src="https://cdn.jsdelivr.net/gh/lemonaaaaa/CDN2/img/codeforces/covers/round-664.png" onerror="this.onerror=null;this.src='https://cdn.jsdelivr.net/gh/lemonaaaaa/CDN/img/404.jpg'" alt="Codeforces Round 664 (Div. 2) 题解"></a></div><div class="recent-post-info"><a class="article-title" href="/2020/08/codeforces-round-664-div2/" title="Codeforces Round 664 (Div. 2) 题解">Codeforces Round 664 (Div. 2) 题解</a><div class="article-meta-wrap"><time class="post-meta__date" title="发表于 2020-08-13 11:57:02"><i class="fa fa-calendar" aria-hidden="true"></i>2020-08-13</time><span class="article-meta"><span class="article-meta__separator">|</span><i class="fa fa-inbox article-meta__icon" aria-hidden="true"></i><a class="article-meta__categories" href="/categories/Code-life/">Code life</a><i class="fa fa-angle-right" aria-hidden="true"></i><i class="fa fa-inbox article-meta__icon" aria-hidden="true"></i><a class="article-meta__categories" href="/categories/Code-life/Codeforces/">Codeforces</a><i class="fa fa-angle-right" aria-hidden="true"></i><i class="fa fa-inbox article-meta__icon" aria-hidden="true"></i><a class="article-meta__categories" href="/categories/Code-life/Codeforces/Round/">Round</a></span></div><div class="content"> A. Boboniu Likes to Color Balls
题目链接
题目原文
题目大意
给出红球的数量，绿球的数量，蓝球的数量，白球的数量，并且你有一次机会将一个红球、一个绿球和一个蓝球都涂成白球。询问是否可能用这些球组成回文串。
解题思路
四种球中如果最多只有一种球为奇数，那么 ...</div></div></div><div class="recent-post-item"><div class="post_cover right_radius"><a href="/2020/08/codeforces-round-663-div2/" title="Codeforces Round 663 (Div. 2) 题解"> <img class="post_bg" src="https://cdn.jsdelivr.net/gh/lemonaaaaa/CDN2/img/codeforces/covers/round-663.png" onerror="this.onerror=null;this.src='https://cdn.jsdelivr.net/gh/lemonaaaaa/CDN/img/404.jpg'" alt="Codeforces Round 663 (Div. 2) 题解"></a></div><div class="recent-post-info"><a class="article-title" href="/2020/08/codeforces-round-663-div2/" title="Codeforces Round 663 (Div. 2) 题解">Codeforces Round 663 (Div. 2) 题解</a><div class="article-meta-wrap"><time class="post-meta__date" title="发表于 2020-08-10 17:48:08"><i class="fa fa-calendar" aria-hidden="true"></i>2020-08-10</time><span class="article-meta"><span class="article-meta__separator">|</span><i class="fa fa-inbox article-meta__icon" aria-hidden="true"></i><a class="article-meta__categories" href="/categories/Code-life/">Code life</a><i class="fa fa-angle-right" aria-hidden="true"></i><i class="fa fa-inbox article-meta__icon" aria-hidden="true"></i><a class="article-meta__categories" href="/categories/Code-life/Codeforces/">Codeforces</a><i class="fa fa-angle-right" aria-hidden="true"></i><i class="fa fa-inbox article-meta__icon" aria-hidden="true"></i><a class="article-meta__categories" href="/categories/Code-life/Codeforces/Round/">Round</a></span></div><div class="content"> A. Suborrays
题目链接
题目原文
题目大意
如果存在一个排列，对于其任意的连续子序列pi…pjp_i \dots p_jpi…pj都满足pi OR pi+1 OR … OR pj⩾j−i+1p_i \;OR \;p_{i+1} \;OR \;\dots \;O ...</div></div></div><nav id="pagination"><div class="pagination"><span class="page-number current">1</span><a class="page-number" href="/page/2/">2</a><span class="space">…</span><a class="page-number" href="/page/4/">4</a><a class="extend next" rel="next" href="/page/2/"><i class="fa fa-fw fa-chevron-right" aria-hidden="true"></i></a></div></nav></div><div class="aside_content" id="aside_content"><div class="card-widget card-info"><div class="card-content"><div class="card-info-avatar is-center"><img class="avatar-img" src="https://cdn.jsdelivr.net/gh/lemonaaaaa/CDN/img/avt-new.jpg" onerror="this.onerror=null;this.src='https://cdn.jsdelivr.net/gh/lemonaaaaa/CDN/img/friend_404.gif'" alt="avatar"/><div class="author-info__name">Lemon</div><div class="author-info__description">A blog recording my life in WHU</div></div><div class="card-info-data"><div class="card-info-data-item 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