Parser: Lpython does not differentiate between keyword and positional arguments in print

[faze-geek]

Came across this in #1512 .

def main():
    print(sep = "++","c", 3, "d", 4, [4, 5, 6])

main()

(lp) C:\Users\kunni\lpython>python try.py
  File "C:\Users\kunni\lpython\try.py", line 2
    print(sep = "++","c", 3, "d", 4, [4, 5, 6])
                                              ^
SyntaxError: positional argument follows keyword argument

(lp) C:\Users\kunni\lpython>src\bin\lpython try.py
c++3++d++4++[4, 5, 6]     # Expected result if sep keyword is mentioned at the end

[harshsingh-24]

What is the exact issue here? @faze-geek
We don't want LPython to print separators, if sep is not present at end and should rather throw an error just like Python?