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Create find-the-maximum-number-of-fruits-collected.cpp
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// Time: O(n^2)
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// Space: O(1)
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// dp
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class Solution {
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public:
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int maxCollectedFruits(vector<vector<int>>& fruits) {
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const int n = size(fruits);
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int result = 0;
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for (int i = 0; i < n; ++i) {
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result += fruits[i][i];
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}
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for (int i = 0; i < n; ++i) {
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for (int j = i + 1; j < n - (i + 1); ++j) {
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fruits[i][j] = 0;
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}
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}
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for (int i = 1; i < n - 1; ++i) {
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for (int j = i + 1; j < n; ++j) {
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fruits[i][j] += max({fruits[i - 1][j - 1], fruits[i - 1][j], j + 1 < n ? fruits[i - 1][j + 1] : 0});
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}
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}
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result += fruits[n - 2][n - 1];
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for (int j = 0; j < n; ++j) {
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for (int i = j + 1; i < n - (j + 1); ++i) {
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fruits[i][j] = 0;
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}
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}
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for (int j = 1; j < n - 1; ++j) {
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for (int i = j + 1; i < n; ++i) {
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fruits[i][j] += max({fruits[i - 1][j - 1], fruits[i][j - 1], i + 1 < n ? fruits[i + 1][j - 1] : 0});
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}
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}
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result += fruits[n - 1][n - 2];
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return result;
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}
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};

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