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tree.symmetric-tree.py

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# Definition for a binary tree node.
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class TreeNode:
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def __init__(self, x):
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self.val = x
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self.left = None
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self.right = None
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class Solution:
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"""
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101. 对称二叉树
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https://leetcode-cn.com/problems/symmetric-tree/
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给定一个二叉树,检查它是否是镜像对称的。
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"""
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def isSymmetric(self, root: TreeNode) -> bool:
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if not root:
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return True
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def dfs(left, right):
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if not left or not right:
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return True
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if not (left and right):
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return False
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if left.val != right.val:
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return False
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return dfs(left.left, right.right) and dfs(left.right, right.left)
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return dfs(root.left, root.right)

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